Answer:
B
Explanation:
graph b shows a steady pace of movement for 20 minutes and then shows a plateau in the distance, showing that while time keeps moving (obviously), the distance doesn't change. then after 5 minutes, the student gets up and starts running again. hope this helped!
A2 = 16 m^2
Explanation:
Application of Pascal's law:
F1/A1 = F2/A2
Given:
F1 = 50 N. A1 = 1 m^2
F2 = 800 N A2 = ?
A2 = (F2/F1)A1 = (800 N/50 N)(1 m^2)
= 16 m^2
The radius of the circle, in cm, after t seconds would be 50t
The area, A, of the circle after t seconds is expressed in the equation: A = pi * r^2
A = pi * (50T)^2 = pi*2500*t^2
The change of area per unit time is obtained by differentiating the equation
A' = pi*2500*2*t A' = pi*5000*t
when t = 3 secondsA' = pi*5000*3 = 47122 cm2/s
Answer:
a = v^2 / R = 4.5^2 / R = 29
R = 4.5^2 / 29 = .70 m
Answer:se obesrva ca indicele de refractie NU are unitate de masura, este adimensional. Se exprima print-un raport, de exemplu 4/3, 1,5 etc.
Explanation:
