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Sveta_85 [38]
2 years ago
7

If an air parcel is given a small push upward and it falls back to its original position, the atmosphere is said to be__________

.
Physics
1 answer:
nydimaria [60]2 years ago
6 0

If an air parcel is given a small push upward and it falls back to its original position, the atmosphere is said to be Stable.

A Stable atmospheric condition is a state where a body thrown like an parcel tends to return to its original position where it was present earlier even after being disturbed externally.

Stable conditions tends to oppose the forces that lead to the displacement of the object from original position.

When a parcel is given a small push upward and it falls back to its original position in air. This shows Stability in the atmosphere which bring back the sir parcel where it was present initially.

A body under the action of gravity in case of stable equilibrium conditions shows returning back of the body after sometime on reaching a certain height.

Learn more about Gravity here, brainly.com/question/4014727

#SPJ4

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Ten identical steel wires have equal lengths L and equal "spring constants" k. The Young's modulus of each wire is Y. The wires
svlad2 [7]

Answer:

option (B)

Explanation:

Young's modulus is defined as the ratio of longitudinal stress to the longitudinal strain.

Its unit is N/m².

The formula for the Young's modulus is given by

Y=\frac{F \times L}{A\times \delta L}

where, F is the force applied on a rod, L is the initial length of the rod, ΔL is the change in length of the rod as the force is applied, A is the area of crossection of the rod.

It is the property of material of solid. So, when the 10 wires are co joined together to form a new wire of length 10 L, the material remains same so the young' modulus remains same.

8 0
3 years ago
A tiger leaps horizontally out of a tree that is 6.00 m high. If he lands 2.00 m from the base of the tree, calculate his initia
Musya8 [376]

Answer:

The initial speed of the tiger is 1.80 m/s

Explanation:

Hi there!

The equation of the position vector of the tiger is the following:

r = (x0 + v0 · t, y0 + 1/2 · g · t²)

Where:

r = position vector at a time t.

x0 = initial horizontal position.

v0 = initial horizontal velocity.

t = time.

y0 = initial vertical position,

g = acceleration due to gravity.

Let´s place the origin of the frame of reference on the ground at the point where the tree is located so that the initial position vector will be:

r0 = (0.00, 6.00) m

We can use the equation of the vertical component of the position vector to obtain the time it takes the tiger to reach the ground.

y = y0 + 1/2 · g · t²

When the tiger reaches the ground, y = 0:

0 = 6.00 m - 1/2 · 9.81 m/s² · t²

2 · (-6.00 m) / -9.81 m/s² = t²

t = 1.11 s

We know that in 1.11 s the tiger travels 2.00 m in the horizontal direction. Then, using the equation of the horizontal component of the position vector we can find the initial speed:

x = x0 + v0 · t

At t = 1.11 s, x = 2.00 m

x0 = 0

2.00 m = v0 · 1.11 s

2.00 m / 1.11 s = v0

v0 = 1.80 m/s

The initial speed of the tiger is 1.80 m/s

4 0
3 years ago
SOMEONE PLSSSS HELP ME WITH THIS QUESTION!!
Hitman42 [59]
The answer is indeed B
4 0
3 years ago
The weight of the atmosphere above 1 m- of
mars1129 [50]

Answer:

1.09 kg.m

Explanation:

no need

4 0
3 years ago
Which statement describes the relationship between bond strength and the melting and boiling points of a substance? A. As the fo
icang [17]

Answer:

a

Explanation:

4 0
3 years ago
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