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4 years ago

Equivalent resistance between A and B.A) 2.4 ohmsB)18 ohmsC) 6 ohmsD) 36 ohms

Physics

2 answers:

IgorLugansk [536]4 years ago

7 0

<h3><u>Answer</u> :</h3>

First of all see the attachment for better understanding $.$ :D

<u>Eq. resistance between C and D</u> :

➝ 1/Rp = 1/6 + 1/6

➝ 1/Rp = 2/6

➝ <u>Rp = 3Ω</u>

<u>E</u><u>q. resistance of upper part </u>:

(All three are in series)

➝ Rs = 3 + 3 + 3

➝ <u>Rs = </u><u>9</u><u>Ω</u>

<u>Eq. resistance of lower part</u> :

(Both are in series)

➝ Rs' = 3 + 3

➝ <u>Rs' = 6Ω</u>

<u>Eq. resistance between A and B </u>:

(Rs and Rs' are in parallel)

➝ 1/Req = 1/Rs + 1/Rs'

➝ 1/Req = 1/9 + 1/6

➝ 1/Req = (2 + 3)/18

➝ Req = 18/5

labwork [276]4 years ago

3 0

Answer:

Explanation:

Eq. resistance between C and D :

➝ Rp = 3Ω

Eq. resistance of upper part :

➝ Rs = 9Ω

Eq. resistance of lower part :

➝ Rs' = 6Ω

Eq. resistance between A and B :

➝ Req = 18/5

➝ Req = 3.6Ω

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An attacker at the base of a castle wall 3.95 m high throws a rock straight up with speed 5.00 m/s from a height of 1.60 m above

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Answer:

a) No

b) the rock must have a minimum initial speed of 6.79m/s for it to reach the top of the building.

Explanation:

Given:

Height of the wall = 3.95m

Initial height = 1.60m

Initial speed = 5.00m/s

distance between the initial height and wall top = 3.95 - 1.60 = 2.35m

Using the formula;

v^2 = u^2 + 2as ....1

Where v = final velocity, u = initial velocity, a = acceleration, s = distance travelled

From equation 1

s = (v^2 - u^2)/2a ...2

Since the rock t moving up,

the acceleration = -g = -9.8m/s2

s = maximum height travelled

v = 0 (at maximum height velocity is zero)

Substituting into equation 2

s = (0 - 5^2)/(2×-9.8) = 1.28m

Therefore, the maximum height is 1.28 from his initial height Which is less than the 2.35m of the wall from his initial height. So the rock will not reach the top of the wall

b) Using equation 1:

u^2 = v^2 - 2as

v = 0

a = -9.8m/s

s = 2.35m. (distance between the initial height and wall top)

u^2 = 0 - 2(-9.8 × 2.35)

u^2 = 46.06

u = √46.06

u = 6.79m/s

Therefore, the rock must have a minimum initial speed of 6.79m/s

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3 years ago

Q15.17 Both wave intensity and gravitation obey inverse-square laws. Do they do so for the same reason?Discuss the reason for ea

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(a) Intensity obeys inverse square law from basis of light passing through a given surface.

(b) Gravitation obeys inverse square law from the basis of force between two masses.

<h3>What is intensity?</h3>

Intensity is the ratio is ratio of power to area of a given surface.

I = P/A (W/m²)

where;

P is power
A is area

<h3>Universal gravitation law</h3>

$F = \frac{Gm_1m_2}{r^2}$

Intensity and gravitation do not obey inverse square law for same reason;

Intensity obeys inverse square law from basis of light passing through a given surface.
Gravitation obeys inverse square law from the basis of force between two masses.

<h3>Acceleration of the block</h3>

a = v²/A

a = (3.9²)/0.12

a = 126.75 m/s²

Learn more about acceleration here: brainly.com/question/605631

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3 years ago

Equivalent resistance between A and B.A) 2.4 ohmsB)18 ohmsC) 6 ohmsD) 36 ohms ​

Equivalent resistance between A and B.A) 2.4 ohmsB)18 ohmsC) 6 ohmsD) 36 ohms