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saul85 [17]
3 years ago
6

A box is being pulled to the right. What is the direction of the gravitational force?

Physics
2 answers:
lapo4ka [179]3 years ago
7 0

The correct answer to the question is vertically downward i.e towards the centre of earth.

EXPLANATION:

As per the question, the box is pulled to the right.

Hence, the direction of the applied force is towards right.

We are asked to determine the direction of the gravitational force that acts on the body.

Before answering this question, first we gave to understand the gravitational force of earth.

Any body present on the surface of earth is attracted with the force of gravity of earth ( gravitational force ) towards its centre.  It is equivalent to the weight of the body.  

The force of gravity is always directed towards the centre of earth irrespective of the nature of applied force.

Hence, the direction of the gravitational force which acts on the box is vertically downward.


dedylja [7]3 years ago
7 0
The direction of the gravitational force is always toward the center
of the Earth.  Wherever you are, it's the direction you call "down".
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In a 400-m relay race the anchorman (the person who runs the last 100 m) for team A can run 100 m in 9.8 s. His rival, the ancho
melisa1 [442]

Answer:

largest lead = 3 m

Explanation:

Basically, this problem is about what is the largest possible distance anchorman for team B can have over the anchorman for team A when the final leg started that anchorman for team A won the race. This show that anchorman for team A must have higher velocity than anchorman for team B to won the race as at the starting of final leg team B runner leads the team A runner.

So, first we need to calculate the velocities of both the anchorman  

given data:

Distance = d = 100 m

Time arrival for A = 9.8 s

Time arrival for B = 10.1 s

Velocity of anchorman A = D / Time arrival for A

=100/ 9.8 = 10.2 m/s

Velocity of anchorman B = D / Time arrival for B

=100/10.1 = 9.9 m/s

As speed of anchorman A is greater than anchorman B. So, anchorman A complete the race first than anchorman B. So, anchorman B covered lower distance than anchorman A. So to calculate the covered distance during time 9.8 s for B runner, we use

d = vt

= 9.9 x 9.8 = 97 m  

So, during the same time interval, anchorman A covered 100 m distance which is greater than anchorman B distance which is 97 m.

largest lead = 100 - 97 = 3 m

So if his lead no more than 3 m anchorman A win the race.

5 0
2 years ago
A dipole of moment 0.5 e·nm is placed in a uniform electric field with a magnitude of 8 times 104 N/C. What is the magnitude of
Over [174]

Answer:

The net torque is zero

Explanation:

Let's assume that the dipole is compose of two equal but oposite charges e, and it cam be represented by a rod with one end having a charge e and the other end with a charge of -e. Notice that the dipole is parallel to the electric field thus the force felt by both of the charges will be parallel to the electric field. This means that there will be no components of the forces that are perpendicular to the rod which is a requirement for it to have a torque.

8 0
3 years ago
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Answer:

True.

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If the sum of the external forces on an object is zero, then the sum of the external torques on it  must also be zero.

The net external force and the net external torque acting on the object have to be zero for an object to be in mechanical equilibrium.

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Answer:

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Explanation:

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