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3 years ago

If you push on the floor with 5 N for 15 seconds, how much work is done?

Physics

2 answers:

Maslowich3 years ago

4 0

Answer: It would be 75

Explanation: If your pushing on the floor at a rate of 5 for 15 seconds you would multiply the numbers and get 75

Schach [20]3 years ago

4 0

15*5=75
The amount of work that is done is 75.

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What is physical quantity

Brums [2.3K]

A physical quantity is a property of a material or system that can be quantified by measurement. A physical quantity can be expressed as the combination of a numerical value and a unit. For example, the physical quantity mass can be quantified as n kg, where n is the numerical value and kg is the unit.

5 0

3 years ago

Read 2 more answers

A bicycle starts at 2.5m/s and accelerates along a straight path to a speed of 12.5m/s in a time of 4.5 seconds. What is the bic

zalisa [80]

Answer:

The bicyclist's acceleration is 2.2m/s^2

Explanation:

Given

$u = 2.5m/s$ ---- Initial Velocity

$v = 12.5m/s$ ---- Final Velocity

$t = 4.5s$ ---- Time

Required

Determine the acceleration

This will be solved using the first equation of motion

$v = u + at$

Substitute values for v, u and a

$12.5 = 2.5 + a * 4.5$

$12.5 = 2.5 + 4.5a$

Collect Like Terms

$4.5a = 12.5 - 2.5$

$4.5a = 10.0$

Solve for a

$a = 10.0/4.5$

$a = 2.2m/s^2$ ---- (approximated)

<em>Hence, the bicyclist's acceleration is 2.2m/s^2</em>

3 0

2 years ago

Describe a device that transforms thermal energy into<br> another useful form.<br> tes that

spin [16.1K]

Answer: heat engine

Explanation:

4 0

2 years ago

Thermopane window is constructed, using two layers of glass 4.0 mm thick, separated by an air space of 5.0 mm.

Bond [772]

To solve this problem it is necessary to apply the concepts related to rate of thermal conduction

$\frac{Q}{t} = \frac{kA\Delta T}{d}$

The letter Q represents the amount of heat transferred in a time t, k is the thermal conductivity constant for the material, A is the cross sectional area of the material transferring heat, $\Delta T$ , T is the difference in temperature between one side of the material and the other, and d is the thickness of the material.

The change made between glass and air would be determined by:

$(\frac{Q}{t})_{glass} = (\frac{Q}{t})_{air}$

$k_{glass}(\frac{A}{L})_{glass} \Delta T_{glass} = k_{air}(A/L)_{air} \Delta T_{air}$

$\Delta T_{air} = (\frac{k_{glass}}{k_{air}})(\frac{L_{air}}{L_{glass}}) \Delta T_{glass}$

$\Delta T_{air} = (\frac{0.84}{0.0234})(\frac{5}{4}) \Delta T_{glass}$

$\Delta T_{air} = 44.9 \Delta T_{glass}$

There are two layers of Glass and one layer of Air so the total temperature would be given as,

$\Delta T = \Delta T_{glass} +\Delta T_{air} +\Delta T_{glass}$

$\Delta T = 2\Delta T_{glass} +\Delta T_{air}$

$20\°C = 46.9\Delta T_{glass}$

$\Delta T_{glass} = 0.426\°C$

Finally the rate of heat flow through this windows is given as,

$\Delta {Q}{t} = k_{glass}\frac{A}{L_{glass}}\Delta T_{glass}$

$\Delta {Q}{t} = 0.84*24*10 -3*0.426$

$\Delta {Q}{t} = 179W$

Therefore the correct answer is D. 180W.

3 0

2 years ago

A 5kg rock and a 10kg rock are dropped from a height of 10m?

fredd [130]

Look out below ! You should step nimbly to one side, to avoid being hit by one or the other of those hazardous weight objects when they arrive (at the same time).

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2 years ago