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jek_recluse [69]
3 years ago
8

If you push on the floor with 5 N for 15 seconds, how much work is done?

Physics
2 answers:
Maslowich3 years ago
4 0

Answer: It would be 75

Explanation: If your pushing on the floor at a rate of 5 for 15 seconds you would multiply the numbers and get 75

Schach [20]3 years ago
4 0
15*5=75
The amount of work that is done is 75.
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What is role of skin in balancing body temperature during strenous excervise
trapecia [35]

Answer:

The skin releases sweat

Explanation:

The body temperature is necessary to maintain homeostasis. Skin  controls body temperature by sweating when it is too heated.

3 0
3 years ago
Two particles each of mass m and charge q are suspended by strings of length / from a common point. Find the angle e that each s
ozzi

Answer:

\theta =\left (\frac{kq^{2}}{4L^{2}\times mg}  \right )^{\frac{1}{3}}

Explanation:

Let the length of the string is L.

Let T be the tension in the string.

Resolve the components of T.

As the charge q is in equilibrium.

T Sinθ = Fe       ..... (1)

T Cosθ = mg     .......(2)

Divide equation (1) by equation (2), we get

tan θ = Fe / mg

tan\theta =\frac{\frac{kq^{2}}{AB^{2}}}{mg}

tan\theta =\frac{\frac{kq^{2}}{4L^{2}Sin^{\theta }}}}{mg}

tan\theta =\frac{kq^{2}}{4L^{2}Sin^{2}\theta \times mg}

tan\theta\times Sin^{2}\theta =\frac{kq^{2}}{4L^{2}\times mg}

As θ is very small, so tanθ and Sinθ is equal to θ.

\theta ^{3} =\frac{kq^{2}}{4L^{2}\times mg}

\theta =\left (\frac{kq^{2}}{4L^{2}\times mg}  \right )^{\frac{1}{3}}

7 0
3 years ago
What is the relation between acceleration due to gravity and radius of the earth? ​
emmasim [6.3K]

Answer:

As the earth is an oblate spheroid, its radius near the equator is more than its radius near poles. Since for a source mass, the acceleration due to gravity is inversely proportional to the square of the radius of the earth, it varies with latitude due to the shape of the earth.

Formula: g = GM/r2

Dimensional Formula: M0L1T-2

Values of g in SI: 9.806 ms-2

Explanation:

Please Mark me brainliest

8 0
3 years ago
Read 2 more answers
How do you calculate resistance with coulombs, time and J's?
Mars2501 [29]
Hey user


The energy E in joules (J) is equal to the voltage V in volts (V), times the electrical charge Q in coulombs (C):

E(J) = V(V) ×<span> Q</span>(C)

So

joule = volt × coulomb

or

J = V × C

Example

What is the energy in joules that is consumed in an electrical circuit with voltage supply of 15V and charge flow of 4 coulombs?

E = 15V × 4C = 60J

4 0
4 years ago
I need help plz and thank you this is do
love history [14]

Answer:

Oh I am sorry this is my first time on brainly i dont how to exit and sorry but dont know the answer

Explanation:

4 0
3 years ago
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