Suppose two point charges, Q1 = +3.37 x 10^-6 C and Q2 = -8.21 x 10^-6 C, are separated by a distance d = 1.99 m.
1 answer:
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The options of the question are missing. I have attached it.
Answer:
Satellite in option B will have the greatest speed.
Explanation:
From kepplers third law, we know that
V² = GM/R
Thus, v = √(GM/R)
Where;
v is velocity
G is gravitational constant
M is mass
R is radius
Looking at the options, let's start from the first one;
Option A
Here, mass = (1/2)m and radius = R
So, v = √(GM/R) thus v = √(G(m/2)/R) = √(Gm/2R)
Option B
Here, mass = m and radius = (1/2)R
Thus v = √(Gm/(R/2)) = √(2Gm/R)
Option C
Here, mass = m and radius = R
Thus v = √(Gm/R)
Option D
Here, mass = m and radius = 2R
Thus v = √(Gm/(2R))
Now, inspecting all the options, it's clear that option B will have the greatest velocity because it's numerator is the biggest and will in turn lead to higher velocity.
Answer:
Because the wavelengths of macroscopic objects are too short for them to be detectable.
Explanation:
Wavelength of an object is given by de Broglie wavelength as:
Where, 'h' is Planck's constant, 'm' is mass of object and 'v' is its velocity.
So, for macroscopic objects, the mass is very large compared to microscopic objects. As we can observe from the above formula, there is an inverse relationship between the mass and wavelength of the object.
So, for vary larger masses, the wavelength would be too short and one will find it undetectable. Therefore, we don't observe wave properties in macroscopic objects.