Question

Suppose two point charges, Q1 = +3.37 x 10^-6 C and Q2 = -8.21 x 10^-6 C, are separated by a distance d = 1.99 m.

Answer 1

Option (C) is the correct one.



Explanation:
Coulmbs law here is,

$\frac{9 \times {10}^{9} \times ( - 8.21 \times {10}^{ - 6} )(3.37 \times {10}^{ - 6} )}{ {(1.99)}^{2} } \\ \\ = - 0.0628$

Which is almost equal to optionC.