Answer:
90 m
Explanation:
We use an ecuation of uniformly accelerated motion, which allows us to find the distance traveled by the car from the moment that driver applies the brakes until it stops completely, that is, when its final speed is zero.
We isolate the variable d, knowing that the final speed is zero
Answer:
The specific gravity of the unkown liquid is 15.
Explanation:
Gauge pressure, at the bottom of the tank in this case, can be calculated from
where and
are the height of the column of oil and the unkown liquid, respectively. Writing for
, we have
Relative to water, the unknow liquid specific weight is 15 times bigger, therefore this is its specific gravity as well.
Answer:
a
The tension in the string is
b
The new balance reading is
Explanation:
From the question we are told that
The mass of the beaker of water is
The diameter of the copper ball is
There are two forces acting on the copper ball
The first is the Buoyant force of the water pushing it up which is mathematically represented as
Where is the density of water which has value of
g is the acceleration due to gravity
is the volume of water displaced by the copper ball which is mathematically evaluated as
The radius r is
Substituting value
Substituting for F
The second force is the weight of the copper ball which is mathematically represented as
Now m is the mass which can be mathematically evaluated as
Where is the density of copper with value of
So
So the weight of copper is
Now the tension the string would be mathematically evaluated as
So
From this value we that the string is holding only 0.85 N of the copper weight thus (0.956 - 0.85 = 0.1065 N ) is being held by the balance
Now the mass equivalent of this weight is mathematically evaluated as
Converting to grams
So the new balance reading is