(a) The force required to remove the sheet increases with increase in speed due to change in magnetic flux.
(b) The area in the magnetic field changes as the sheet is being put in between the poles. Thus, a force would be required to put the sheets.
<h3>Change in magnetic flux </h3>
When the sheet is pulled out, from the electromagnet there is change in magnetic flux given as follows;
Ф = BA
where;
- B is magnetic field
- A is area
emf = dФ/dt
F = qVB
Thus, the force required to remove the sheet increases with increase in speed due to change in magnetic flux.
Also, the area in the magnetic field changes as the sheet is being put in between the poles. Thus, a force would be required to put the sheets.
Learn more about magnetic flux here: brainly.com/question/10736183
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I'm pretty sure that the "block" of which you speak is one in a pattern
of them that covers the drawing you have of the rectangle, and now
I need to explain something to you:
The REASON for printing that drawing next to the question that you
partially copied is that the drawing has information that's needed to
answer the question with, and rather than repeat all that information
in the question, it just says "LOOK AT THE DRAWING !"
In fact, the whole point of the question may not be just to remind you of
what "perimeter" means. It's more likely that the purpose of this problem
is to make you pick the information you need off of a drawing.
Either way, if you'll kind of "read between the lines" of the part of the
question that you DID copy, it should be pretty obvious to you that nobody's
going nowhere in the direction of a solution without SEEing the drawing.
So my bottom-line conclusion regarding a solution for this problem is:
Not possible with the given information.
Answer:
a. A list of the names of each student present today. (microstate)
b. The number of students in attendance. (macrostate)
Explanation:
You can fins the answer to this question by comparing the situation of the problem with a system of molecules with discrete energy.
Without importance of which molecules have a specific energy, but rather, what is the total amount of energy, you can get for different configurations of energy the same amount of the total energy. If different configurations of the energies of the molecules give you the same total energy of the system, you say that the macrostate is the same. In the case of the classroom, it does not matter how are distributed the students in the class, the total number of students is always the same. The macrostate is the same for what ever organization of the students in the class.
If you would interested in the energy of each molecules, you will obtain different configurations. In the case of the classroom. The names of the student will define a microstate because in this case there are many configurations.
a. A list of the names of each student present today. (microstate)
b. The number of students in attendance. (macrostate)
The question is incomplete. The complete question is :
In your job as a mechanical engineer you are designing a flywheel and clutch-plate system. Disk A is made of a lighter material than disk B, and the moment of inertia of disk A about the shaft is one-third that of disk B. The moment of inertia of the shaft is negligible. With the clutch disconnected, A is brought up to an angular speed ?0; B is initially at rest. The accelerating torque is then removed from A, and A is coupled to B. (Ignore bearing friction.) The design specifications allow for a maximum of 2300 J of thermal energy to be developed when the connection is made. What can be the maximum value of the original kinetic energy of disk A so as not to exceed the maximum allowed value of the thermal energy?
Solution :
Let M.I. of disk A = 
So, M.I. of disk B = 
Angular velocity of A = 
So the kinetic energy of the disk A = 
After coupling, the angular velocity of both the disks will be equal to ω.
Angular momentum will be conserved.
So,



Now,






Therefore, the maximum initial K.E. = 3066.67 J
Answer:
t = 1.22 s
Explanation:
Given that,
The initial upward velocity component of a football = 12 m/s
The horizontal velocity component is 20 m/s
We need to find the time required for the football to reach the highest point of the trajectory. Let the time is t.
Using first equation of motion to solve it such that,

u is initial velocity
v is final velocity
a = -g
so,

So, the required time taken by the football to reach the highest point is 1.22 seconds.