Answer:
The composition of Mg(OH)2 is
41.67 % Mg,
54.87 % O
3.457 % H
Explanation:
Thats the percent composition for each one in your question
The building of all the profiles is correct; The total number of electrons is correct, as well as the filling of the shells to their entirety. However, some charge calculations are off. First, we see that sodium loses an electron in its structure. Hence, it acquires a charge of +1, not -1. Also, Fluorine gains 2 electrons in its 2p subshell. Thus, its charge is -2, not -1 and this is wrong too. The only correct answer is C; aluminum lose 3 electrons from its p-shell and hence it has a charge of +3.
C3H6Br2 2 isomers:- bominated allkane
CH3CH2CHBr2 1,1-dibromopropane
<span>CH3CHBrCH2Br 1,2-dibromopropane
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Answer:
Students communicate results in laboratory reports, and professional scientists communicate results in scientific journals.
Explanation:
This is the answer i just did it.
I hope this helps.
A I think but IM NOT SURE
