Half reaction :
Oxidation
Cu ⇒ Cu²⁺ + 2e⁻
Reduction
2Ag⁺+ 2e⁻ ⇒2Ag
<h3>Further explanation</h3>
Given
Reaction
Cu+2AgNO₃⇒Cu(NO₃)₂+2Ag
Required
Oxidation and reduction half-reactions
Solution
Oxidation is an increase in oxidation number, while reduction is a decrease in oxidation number.
Cu ⇒ Cu²⁺ + 2e⁻
0 to +2
2Ag⁺+ 2e⁻ ⇒2Ag
+1 to 0
Answer:
1.605cm = 4 significant figures
16.050cm = 4 significant figures
16.050cm = 4 significant figures
12 + 12.5 + 125 = 149.5 = 4 significant figures
1.62 × 10^3/2.8 × 10^-5 = 1620/0.000028 = 11 significant figures
Answer:
1.) At high altitude it takes longer to cook spaghetti.
Explanation:
The first even describes depression in boiling point due to reduction in external pressure . It is not a colligative property.
Depression of freezing point and elevation of boiling point due to impurity or addition of solute are colligative priperty.
Is that all you have...............................................................