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1 year ago

How is polypropylene commonly used?

1 answer:

8 0

In its fibre form, polypropylene uses are not limited to not only useful for tote bags but also encompass a much wider range of other products, including ropes, twine, tape, carpets, upholstery, clothing and camping equipment.

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What did you observe<br> when heat was added to the penny with iodine?

Andru [333]

This is a difficult task because zinc is much more active than copper and could hardly be passivated. ... The sur- face immediately turns white (the color of copper(I) iodide) and the yellow-brown color of iodine quickly fades. Rinse the coin with water, brighten it with polish and cloth and begin the whole process again.N

8 0

2 years ago

A gas mixture with 4 mol of Ar, x moles of Ne, and y moles

maks197457 [2]

Answer:

a) $\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

b) $x=4$

c) $\Delta G_{max}=-2721.9 J/mol$

Explanation:

Gas mixture:

$n_{Ar}= 4 mol$

$n_{Ne}= x mol$

$n_{Xe}= y mol$

$n_{tot}= n_{Ar} + n_{Ne} + n_{Xe}=3*n_{Ar}$

$n_{Ne} + n_{Xe}=2*n_{Ar}$

$x + y=8 mol$

$y=8 mol- x$

Mol fractions:

$x_{Ar}=\frac{4 mol}{12 mol}=1/3$

$x_{Ne}=\frac{x mol}{12 mol}=x/12$

$x_{Xe}=\frac{8 - x mol}{12 mol}=(8-x)/12$

Expression of $\Delta G_{mixing}$

$\Delta G_{mixing}=R*T*\sum_{i]*x_i*ln (x_i)$

$\Delta G_{mixing}=R*T*[1/3*ln (1/3) +x/12*ln (x/12) +(8-x)/12*ln ((8-x)/12)]$

$\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

Expression of $\Delta G_{max}$

$\frac{d \Delta G_{mixing}}{dx}=0$

$\frac{d \Delta G_{mixing}}{dx}=\frac{R*T}{12}*[ln (x/12)+12-ln ((8-x)/12)-12]$

$0=\frac{R*T}{12}*[ln (x/12)-ln ((8-x)/12)$

$0=[ln (x/12)-ln ((8-x)/12)$

$ln (x/12)=ln ((8-x)/12)$

$x=(8-x)$

$x=4$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (4/12) +(8-4)*ln ((8-4)/12)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (1/3) +(4)*ln (1/3)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[12*ln (1/3)]$

$\Delta G_{max}=-2721.9 J/mol$

4 0

3 years ago

Which of the following has a mass of 10.0 g?

Serjik [45]

Answer:

a. 0.119mol Kr

Explanation:

To solve this problem, we must understand that;

Mass = number of moles x molar mass

Molar mass of Kr = 83.3g/mol

Ar = 40g/mol

He = 4g/mol

Ne = 20.18g/mol

a0.119 mol Kr mass = 0.119 x 83.3 = 9.9g

b 0.400 mol Ar mass = 0.4 x 40 = 16g

C 1.25 mol He mass = 1.25 x 4 = 5g

d 2.02 mol Ne mass = 2.02 x 20.18 = 40.8

Krypton is the answer

5 0

2 years ago

Assume that there is a puddle that contains 12.0 kg of water and it froze outside since it is -1°C. The

Musya8 [376]

The temperature that must be to freeze the solution would be -21.1 ° C.

<h3>How to calculate the freezing temperature of this solution?</h3>

To calculate the freezing temperature we must take into account the following information.

Solution with a salt concentration of 10% is frozen at -6°C
Solution with a salt concentration of 20% is frozen at -16°C
Solution with a higher concentration is frozen at -21.1°C

According to the above, it can be inferred that the puddle has a 50% concentration of salt because they had 12 kg of water and 6 kg of salt.

So the lowest freezing temperature would be 21.1°C because the puddle is 50% concentrated.

Note: This question is incomplete because there is some missing information. Here is the missing information:

A 10% salt solution freezes at about 20°F (-6°C), and a 20% solution freezes at 2°F (-16°C).
The lowest freezing point obtainable for salt solutions is −21.1 °C

Learn more about freezing in: brainly.com/question/14131507

4 0

2 years ago

Why do we call meteors shooting stars?

zlopas [31]

They burn up and cause it to look like shooting stars

6 0

3 years ago