uhh , not all girls are like that. many of em these days are more career oriented and thats good i guess , so if anything ur just being judgy a f here.
Answer:
Gravitational; strongest; facing; closer; near side; toward.
Explanation:
The gravitational attraction between the Earth and the moon is strongest on the side of the Earth that happens to be facing the moon, simply because it is closer. This attraction causes the water on this “near side” of Earth to be pulled toward the moon. These forces of attraction and inertia tends to keep the water in place and consequently, leads to a bulge of water on the near side with respect to the moon.
Also, you should note that what is responsible for the moon being in orbit around the Earth is the gravitational force of attraction between the two planetary bodies (Earth and Moon).
is the volume of the sample when the water content is 10%.
<u>Explanation:</u>
Given Data:
![V_{1}=100\ \mathrm{ft}^{3}](https://tex.z-dn.net/?f=V_%7B1%7D%3D100%5C%20%5Cmathrm%7Bft%7D%5E%7B3%7D)
First has a natural water content of 25% =
= 0.25
Shrinkage limit, ![w_{1}=12 \%=\frac{12}{100}=0.12](https://tex.z-dn.net/?f=w_%7B1%7D%3D12%20%5C%25%3D%5Cfrac%7B12%7D%7B100%7D%3D0.12)
![G_{s}=2.70](https://tex.z-dn.net/?f=G_%7Bs%7D%3D2.70)
We need to determine the volume of the sample when the water content is 10% (0.10). As we know,
![V \propto[1+e]](https://tex.z-dn.net/?f=V%20%5Cpropto%5B1%2Be%5D)
------> eq 1
![e_{1}=\frac{w_{1} \times G_{s}}{S_{r}}](https://tex.z-dn.net/?f=e_%7B1%7D%3D%5Cfrac%7Bw_%7B1%7D%20%5Ctimes%20G_%7Bs%7D%7D%7BS_%7Br%7D%7D)
The above equation is at
,
![e_{1}=w_{1} \times G_{s}](https://tex.z-dn.net/?f=e_%7B1%7D%3Dw_%7B1%7D%20%5Ctimes%20G_%7Bs%7D)
Applying the given values, we get
![e_{1}=0.25 \times 2.70=0.675](https://tex.z-dn.net/?f=e_%7B1%7D%3D0.25%20%5Ctimes%202.70%3D0.675)
Shrinkage limit is lowest water content
![e_{2}=w_{2} \times G_{s}](https://tex.z-dn.net/?f=e_%7B2%7D%3Dw_%7B2%7D%20%5Ctimes%20G_%7Bs%7D)
Applying the given values, we get
![e_{2}=0.12 \times 2.70=0.324](https://tex.z-dn.net/?f=e_%7B2%7D%3D0.12%20%5Ctimes%202.70%3D0.324)
Applying the found values in eq 1, we get
![\frac{V_{2}}{100}=\frac{1+0.324}{1+0.675}=\frac{1.324}{1.675}=0.7904](https://tex.z-dn.net/?f=%5Cfrac%7BV_%7B2%7D%7D%7B100%7D%3D%5Cfrac%7B1%2B0.324%7D%7B1%2B0.675%7D%3D%5Cfrac%7B1.324%7D%7B1.675%7D%3D0.7904)
![V_{2}=0.7904 \times 100=79\ \mathrm{ft}^{3}](https://tex.z-dn.net/?f=V_%7B2%7D%3D0.7904%20%5Ctimes%20100%3D79%5C%20%5Cmathrm%7Bft%7D%5E%7B3%7D)