1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
masya89 [10]
4 years ago
5

Water flowing through both a small pipe and a large pipe can fill a water tank in 4 hours. Water flowing through the small pipe

alone can fill the tank in 15 more hours. How many hours would it take to fill the tank using only the small pipe?
Engineering
1 answer:
Alex_Xolod [135]4 years ago
7 0

Answer with explanation:

As is the question the answer would be 19 hours, and the key to solving it is in the phrase in 15 more hours, basically what they are saying is that the small pipe takes 15 hours more than both the big and the small to fill the tank. Since both pipes working together can fill the tank in 4 hours we need to add 4 and 15 to solve the problem.

If the question is how many hours would it take to fill the tank using only the big pipe? Then we could solve t for the following equation:

\frac{1}{4+15} + \frac{1}{t}  = \frac{1}{4}

Getting as a result: 5.06

Note that the equation is the result of taking the rate of the small pipe (what we solved before), plus the unknown rate of the big one equals the rate of both.

You might be interested in
Source 1 can supply energy at the rate of 11000 kJ/min at 310°C. A second Source 2 can supply energy at the rate of 110000 kJ/mi
VladimirAG [237]

Answer:

Source 2.

Explanation:

The efficiency of the ideal reversible heat engine is given by the Carnot's power cycle:

\eta_{th} = 1 - \frac{T_{L}}{T_{H}}

Where:

T_{L} - Temperature of the cold reservoir, in K.

T_{H} - Temperature of the hot reservoir, in K.

The thermal efficiencies are, respectively:

Source 1

\eta_{th} = 1 - \frac{311.15\,K}{583.15\,K}

\eta_{th} = 0.466 \,(46.6\,\%)

Source 2

\eta_{th} = 1 - \frac{311.15\,K}{338.15\,K}

\eta_{th} = 0.0798 \,(7.98\,\%)

The power produced by each device is presented below:

Source 1

\dot W = (0.466)\cdot (11000\,\frac{kJ}{min})\cdot (\frac{1\,min}{60\,s} )

\dot W = 85.433\,kW

Source 2

\dot W = (0.0798)\cdot (110000\,\frac{kJ}{min})\cdot (\frac{1\,min}{60\,s} )

\dot W = 146.3\,kW

The source 2 produces the largest amount of power.

8 0
3 years ago
Do the coil resistances have any effect on the plots?
PolarNik [594]
Because of the skin depth effect, the current at high frequency tends to flow at very low depth from radius. Then at high frequency the effective cross section of the wire is narrower than at DC.

Fro example skin depth at 100 kHz is 0.206 mm (0.008”), a wire more thicker than AWG26 could be a waste of copper, better use a bunch of thin wire (Litz wire) to rise the Q factor.
8 0
3 years ago
A gas cylinder is connected to a manometer that contains water. The other end of the manometer is open to the atmosphere, which
horrorfan [7]

Answer: the absolute static pressure in the gas cylinder is 82.23596 kPa

Explanation:

Given that;

patm = 79 kPa, h = 13 in of H₂O,

A sketch of the problem is uploaded along this answer.

Now

pA = patm + 13 in of H₂O ( h × density × g )

pA= 79 + (13 × 0.0254 × 9.8 × 1000/1000)

pA = 82.23596 kPa

the absolute static pressure in the gas cylinder is 82.23596 kPa

4 0
4 years ago
A single-degree-of-freedom mass-spring-damper system is observed during its free vibration and the displacement amplitude decays
AleksandrR [38]

Answer:

Logarithmic decrement is equal to 0.182

Explanation:

given,

amplitude decay = 9 dB          

number of cycles = 12 cycles        

mass of the system = 7 kg        

spring stiffness = 3000 N/m            

logarithmic decrement = ?                  

now,                                                      

logarithmic decreament = ln\ D^{\frac{1}{n}}

                                        = ln\ 9^{\frac{1}{12}}

                                        =ln (1.2)

                                        = 0.182

Hence, Logarithmic decrement is equal to 0.182

5 0
4 years ago
A(n) ____________________ measures the resistance to current flow in a circuit.
yulyashka [42]

Answer: OHMMETER & MEGOHMMETER:

Explanation: The ohmmeter measures circuit resistance; the megohmmeter measures the high resistance of insulation. A meter used to measure electric current. It is connected as part of a circuit.

6 0
3 years ago
Other questions:
  • A vegetable freezing plant requires 35 tons of refrigeration. The freezing temperature is – 38°C while the ambient temperature i
    14·1 answer
  • WILL GIVE BRAINLIEST
    11·1 answer
  • What is the main purpose of the alternator?
    13·1 answer
  • The natural water content of a Boston Blue Clay soil sample was found to be 14.6% through oven drying. It has been calculated th
    8·1 answer
  • Multiple Choice
    5·1 answer
  • Please help ASAP!!
    11·1 answer
  • Implement the following Matlab code:
    8·1 answer
  • Select the correct answer.
    6·1 answer
  • (a) calculate the moment at point "c", where point "c" is the square 3'' below the centroid
    13·1 answer
  • Footing: This is a 3 m wide strip footing, located on the ground surface of an isotropic, homogeneous
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!