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masya89 [10]
4 years ago
5

Water flowing through both a small pipe and a large pipe can fill a water tank in 4 hours. Water flowing through the small pipe

alone can fill the tank in 15 more hours. How many hours would it take to fill the tank using only the small pipe?
Engineering
1 answer:
Alex_Xolod [135]4 years ago
7 0

Answer with explanation:

As is the question the answer would be 19 hours, and the key to solving it is in the phrase in 15 more hours, basically what they are saying is that the small pipe takes 15 hours more than both the big and the small to fill the tank. Since both pipes working together can fill the tank in 4 hours we need to add 4 and 15 to solve the problem.

If the question is how many hours would it take to fill the tank using only the big pipe? Then we could solve t for the following equation:

\frac{1}{4+15} + \frac{1}{t}  = \frac{1}{4}

Getting as a result: 5.06

Note that the equation is the result of taking the rate of the small pipe (what we solved before), plus the unknown rate of the big one equals the rate of both.

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6 0
3 years ago
Which of the following material properties varies with temperature? a)- density b)- viscosity c)- electrical resistance d)- all
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(d) all of the above

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Effect on the density of temperature: If we increase the temperature of any room then particles of the room moves and to and fro and so density is decrease

Effect on the viscosity  of temperature : viscosity is inversely proportional to the temperature if we increase the temperature viscosity decreases and if we decrease the temperature viscosity increases.

Effect on the resistance of temperature : For metals if we increase the temperature then resistance increases and for semiconductor if we increase the temperature resistance decreases

So from above discussion all the parameter depends on the temperature so option (d( will be the correct option  

6 0
3 years ago
For a metal that has an electrical conductivity of 6.1 × 107 (Ω∙m)–1, what is the resistance of a wire that is 4.3 mm in diamete
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Answer: (C) 9.14 . 10⁻³ Ω

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The resistance of a resistor, is proportional to his length and inversely proportional to his area, being the proportionality constant a property of the material, called resistivity.

The resistivity  is defined as the inverse of  the electrical conductivity, which depends on the number of charge carriers  and the mobility of these carriers, which is different for each material.

So, we can calculate the resistance as follows:

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R = 1/6.1. 10⁷ (Ω.m) . 8.1 m. / π (0.0043)² m / 4 = 9.14 . 10⁻³ Ω

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