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FinnZ [79.3K]
3 years ago
9

What are similarities between global warming and the greenhouse effect

Chemistry
1 answer:
n200080 [17]3 years ago
6 0
The greenhouse effect is rightly called that because greenhouses allow heat to enter, but doesn't allow heat to leave, which warms plants.

On earth however, it's much bigger. Our own atmosphere acts similarly to this; it allows heat in, but doesn't allow it to leave which heats up the planet and causes global warming.
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What volume would a 23.8 g sample of sulfur dioxide take up if it were stored at STP7
IceJOKER [234]

Answer:

Hh

Explanation:

Bb

4 0
3 years ago
An airplane travels with a constant velocity of 210 m/s and in the upper atmosphere where the plane is traveling there is a wind
kolezko [41]

Answer:

hello your question is incomplete the options are missing

Determine the resultant velocity for the plane when it is travelling

i) To the east

ii) To the west

answer :i)  270 i

             ii)  -150 i

Explanation:

velocity of Airplane = 210 m/s

wind velocity = 60 m/s to the east

The resultant velocity for the plane when it is travelling  

let the velocity of the wind = V2

           velocity of the plane = v1

i) The resultant velocity for the plane when travelling to the east

Vr = V2 i  + V1 i

Vr= 60i + 210i  = 270i

ii) resultant velocity when the plane is travelling to the west

Vr = - V1 i + V2i

     = -210i  + 60 i = -150 i  

4 0
3 years ago
There are approximately 15 milliliters (mL) in 1 tablespoon (tbsp). Which expression can be used to find the approximate number
Helga [31]
You know 1 tbsp is 15 milliliters so you would multiply 15 and 3 together. 15 x 3 =45
So there are 45 milliliters in 3 tbsp.
8 0
3 years ago
Read 2 more answers
Intravenous saline solutions are often administered to patients in the hospital. Normal saline solution containers has a concent
zalisa [80]

0.02 mol NaCl

Explanation:

(0.2M NaCl)×(0.10 L) = 0.02 mol NaCl

8 0
3 years ago
A sample of 0.3283 g of an ionic compound containing the bromide ion (Br−) is dissolved in water and treated with an excess of A
Pavel [41]

Answer:

92.49 %

Explanation:

We first calculate the number of moles n of AgBr in 0.7127 g

n = m/M where M = molar mass of AgBr = 187.77 g/mol and m = mass of AgBr formed = 0.7127 g

n = m/M = 0.7127g/187.77 g/mol = 0.0038 mol

Since 1 mol of Bromide ion Br⁻ forms 1 mol AgBr, number of moles of Br⁻ formed = 0.0038 mol and

From n = m/M

m = nM . Where m = mass of Bromide ion precipitate and M = Molar mass of Bromine = 79.904 g/mol

m = 0.0038 mol × 79.904 g/mol = 0.3036 g

% Br in compound = m₁/m₂ × 100%

m₁ = mass of Br in compound = m = 0.3036 g (Since the same amount of Br in the compound is the same amount in the precipitate.)

m₂ = mass of compound = 0.3283 g

% Br in compound = m₁/m₂ × 100% = 0.3036/0.3283 × 100% = 0.9249 × 100% = 92.49 %

4 0
3 years ago
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