Answer:
a) 
b) entropy of the sistem equal to a), entropy of the universe grater than a).
Explanation:
a) The change of entropy for a reversible process:
The energy balance:
![\delta U=[tex]\delta Q- \delta W](https://tex.z-dn.net/?f=%5Cdelta%20U%3D%5Btex%5D%5Cdelta%20Q-%20%5Cdelta%20W)
If the process is isothermical the U doesn't change:
![0=[tex]\delta Q- \delta W](https://tex.z-dn.net/?f=0%3D%5Btex%5D%5Cdelta%20Q-%20%5Cdelta%20W)
The work:
If it is an ideal gas:
Solving:
Replacing:
Given that it's a compression: V2<V1 and ln(V2/V1)<0. So:
b) The entropy change of the sistem will be equal to the calculated in a), but the change of entropy of the universe will be 0 in a) (reversible process) and in b) has to be positive given that it is an irreversible process.
Answer:
12 átomos de oxígeno hay presentes
Explanation:
Basados en la reacción:
6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂
<em>6 moles de agua producen 1 mol de glucosa</em>
<em />
Si reaccionan 12 moleculas de agua, se producirán:
12 moleculas H₂O * (1 mol C₆H₁₂O₆ / 6 mol H₂O) =
2 moléculas de glucosa se producen.
Como cada molécula de glucosa tiene 6 átomos de oxígeno:
2 moléculas C₆H₁₂O₆ * (6 átomos Oxígeno / 1 molécula C₆H₁₂O₆) =
<h3>12 átomos de oxígeno hay presentes</h3>
Answer:
A. stored energy
Explanation:
potential energy is stored energy.
kinetic energy is the energy of motion
Yes it is oxygen it is right i had this question on my test before
Answer:
1.84 D, pointing to the O atom from the midpoint of the line joining the two H nuclei.
Step-by-step explanation:
(1) <em>Direction
</em>
O is more electronegative than H, so an O_H bond dipole points from H to O along the bond axis.
There are two O-H bonds, so the net dipole points to the O atom from the midpoint of the line joining the two H nuclei (see diagram).
(2) <em>Magnitude
</em>
The net dipole moment of water is the vector sum of the two O-H bond dipoles (1.50 D).
Consider the contribution from one O-H bond dipole.
The H-O-H bond angle of water is 104.5°.
Half that value is 52.25 °.
µ = 1.50(cos52.25°) = 1.50 × 0.6122 = 0.918
There are two bond dipoles, so the net molecular dipole is
µ = 2 × 0.918 D = 1.84 D
