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asambeis [7]
3 years ago
6

Generally, what happens to the rate of dissolution for a solid solute when you change from stirring a solution to not stirring i

t?
Chemistry
2 answers:
Anna35 [415]3 years ago
8 0

Explanation:

When we stir the solute in a solution then rate of dissolution increases as size of solute particles rapidly decreases on stirring.

On the other hand, when we do not stir the solute in a solution then rate of dissolution decreases.

For example, when we stir salt in water it readily dissolves but when we do not stir salt in water then either it takes long time to dissociate or it does not get dissolved.

Makovka662 [10]3 years ago
6 0
The rate of dissolution of a solid solute into the solution decreases when you stop stirring it. Generally, stirring increases the dissolution rate of a solid into a solution. An example is coffee with sugar, the sugar dissolves faster when stirred versus when left to dissolve on its own.
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Ira Lisetskai [31]

Answer:

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support students as they build complex explanations

of the unit’s anchor phenomenon. The Coherence

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Explanation:

7 0
2 years ago
Cu + 2AgNO3 es002-1.jpg 2Ag + Cu(NO3)2 How many moles of copper must react to form 0.854 mol Ag?
marin [14]
Balance Chemical Equation is as follow,

<span>                        Cu + 2 AgNO</span>₃     →    2 Ag + Cu(NO₃)₂

According to Balance Equation,

                   2 Moles of Ag is produced by reacting  =  1 Mole of Cu
So, 
     0.854 Moles of Ag will be produced by reacting  =  X Moles of Cu

Solving for X,
                             X  =  (0.854 mol × 1 mol) ÷ 2 mol

                             X  =  0.427 Moles of Cu
Result:
            0.854 Moles of Ag 
are produced by reacting 0.427 Moles of Cu.
4 0
3 years ago
When designing a experiment, a__________ is always needed to ensure you are able to compare.
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Answer:

hypothesis

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3 0
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Write a balanced chemical equation, including physical state symbols, for the combustion of gaseous butane into gaseous carbon d
Phantasy [73]

Answer:1.

1.Balanced equation

C4H10 + 9 02 ==> 5H20 +4CO2

2. Volume of CO2 =596L

Explanation:

1.Combustion of alkane is the reaction of alkanes with Oxygen. And the general equation for the combustion is;

CxHy +( x+y/4) O2 ==> y/2 02 + xCO2

Where x and y are number of carbon and hydrogen atoms respectively.

For butane (C4H10)

x=4 and y=10

Therefore

C4H10 + 9 02 ==> 5H20 +4CO2

2. Mass of butane = 0.360kg

Molar mass of C4H10 = ( 12×4 + 1×10)

= 48 +10=58g/mol= 0.058kg/mol

Mole = mass/molar mass

Mole = 0.360/0.058= 6.2moles

From the stoichiometric equation

1mole of C4H10 will gives 4moles of CO2

Therefore

6.2moles of C4H10 will gives 4 moles of 24.8 moles of CO2

Using the ideal gas equation

PV=nRT

P= 1.0atm

V=?

n= 24.8mol.

R=0.08206atmL/molK

T=20+273=293

V= 24.8 × 0.08206 × 293

V= 596L

Therefore the volume of CO2 produced is 596L

8 0
3 years ago
What should i paint?
Vladimir [108]
A hedgehog! they’re adorable
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3 years ago
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