Answer:
When the excited electron fall back to the lower energy levels the energy is released in the form of radiations.The characteristics bright colors are due to the these emitted radiations. These emitted radiations can be seen if they are fall in the visible region of spectrum
Explanation:
The electron is jumped into higher level and back into lower level by absorbing and releasing the energy.
The process is called excitation and de-excitation.
Excitation:
When the energy is provided to the atom the electrons by absorbing the energy jump to the higher energy levels. This process is called excitation. The amount of energy absorbed by the electron is exactly equal to the energy difference of orbits. For example if electron jumped from K to L it must absorbed the energy which is equal the energy difference of these two level. The excited electron thus move back to lower energy level which is K by releasing the energy because electron can not stay longer in higher energy level and comes to ground state.
De-excitation:
When the excited electron fall back to the lower energy levels the energy is released in the form of radiations. this energy is exactly equal to the energy difference between the orbits. The characteristics bright colors are due to the these emitted radiations. These emitted radiations can be seen if they are fall in the visible region of spectrum
The effusion rate is 1.125 cm/sec for ammonia.
How to find effusion rate ?
Effusion rate (r1) HCl = 43.2 cm/min
Molar mass (m2) NH3 =17.04g/mole
Molar mass (m1) HCl =36.46g/mole
- Substitute the molar masses of the gases into Graham's law and solve for the ratio.
firstly convert 43.2 cm/min into cm/sec i.e., 0.72 cm/sec
Then,
0.72/r2 =√17.04/36.46
r2= 1.125 cm/sec
Hence, the rate of diffusion of ammonia is 1.125 times faster than the rate of diffusion of hydrogen chloride.
learn more about effusion here:
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Answer:
BrF3 has 2 lone pairs (4 unshared electrons)
Explanation:
Pretty sure the answer is 23^4-20=54
