Which represents newton's second law? a v=d/t b a=f/m c f=mv d f=0?

What are the requirements for chemical labels

yaroslaw [1]

A chemical label should include: a product identifier, signal word, hazard statement, precautionary statement,pictorgrams and supplier information

Explanation:

The product identifier : positioned at the upper left end corner of the label gives the identity of the hazardous chemical by appropriate terms. i.e. the name and code

Signal word: The "Danger" and "WARNING" words. The former is used for a more severe hazard where as the former is for a less severe hazard

Hazard statement : gives a description of the nature and degree of hazard of the chemical

Precautionary statements : Put for workers and users on ways to minimize exposure and lower risks in event of contact with the harmful chemical

Supplier information : It has the chemical manufacturer details such as name, location and telephone number.

Pictograms : Normally symbols with red borders for visual illustration of the hazard chemical.

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Chemical labels : brainly.com/question/3115518

Keywords : chemical, labels

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3 0

4 years ago

A soccer ball is kicked from the top of one building with a height of H1 = 30.2 m to another building with a height of H2 = 12.0

viktelen [127]

Hi there!

Initially, we have gravitational potential energy and kinetic energy. If we set the zero-line at H2 (12.0m), then the ball at the second building only has kinetic energy.

We also know there was work done on the ball by air resistance that decreased the ball's total energy.

Let's do a summation using the equations:
$KE = \frac{1}{2}mv^2 \\\\PE = mgh$

Our initial energy consists of both kinetic and potential energy (relative to the final height of the ball)

$E_i = \frac{1}{2}mv_i^2 + mg(H_1 - H_2)$

Our final energy, since we set the zero-line to be at H2, is just kinetic energy.

$E_f = \frac{1}{2}mv_f^2$

And:
$W_A = E_i - E_f$

The work done by air resistance is equal to the difference between the initial energy and the final energy of the soccer ball.

Therefore:
$W_A = \frac{1}{2}mv_i^2 + mg(H_1 - H_2) - \frac{1}{2}mv_f^2$

Solving for the work done by air resistance:
$W_A = \frac{1}{2}(.450)(15.1^2)+ (.450)(9.8)(30.2 - 12) - \frac{1}{2}(.450)(19.89^2)$

$W_A = \boxed{42.552 J}$

8 0

2 years ago

In a shot-put competition, a shot moving at 15m/s has 450J of mechanical kinetic energy. What is the mass of the shot? Please he

Llana [10]

Answer:

Mass of shot (m) = 4 kg

Explanation:

Given:

Velocity (v) = 15 m/s

Mechanical kinetic energy (K.E) = 450 J

Find:

Mass of shot (m) = ?

Computation:

Mechanical kinetic energy (K.E) = 1/2mv²

Mechanical kinetic energy (K.E) = [1/2](m)(15)²

450 = [1/2](m)(15)²

900 = 225 m

Mass of shot (m) = 4 kg

5 0

3 years ago

Thiết bị nào sau đây không phải là nguồn điện

kumpel [21]

Thiết bị không phải nguồn điện:

Đáp án D

7 0

3 years ago

Explain how your battery works. (You may want to look at the Electric Current lesson) What are some possible materials you could

Lisa [10]

Answer:

A battery is made up of three parts. The Cathode (positive end +) , the Anode (negative end -) and the electrolyte. The electrolyte allows electrical charges to travel between the cathode and anode. This chemical reactions creates the flow of electricity supplying the electrical voltage potential to power a circuit.

Typical materials of a battery are as follows

- Anode most often is made of zinc

- Manganese dioxide acting as Cathode.

- the electrolyte between and inside contains ions

Explanation:

6 0

3 years ago