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harkovskaia [24]
3 years ago
7

In a shot-put competition, a shot moving at 15m/s has 450J of mechanical kinetic energy. What is the mass of the shot? Please he

lp, and include the formula for the answer and a step by step explanation
Physics
1 answer:
Llana [10]3 years ago
5 0

Answer:

Mass of shot (m) = 4 kg

Explanation:

Given:

Velocity (v) = 15 m/s

Mechanical kinetic energy (K.E) = 450 J

Find:

Mass of shot (m) = ?

Computation:

Mechanical kinetic energy (K.E) = 1/2mv²

Mechanical kinetic energy (K.E) = [1/2](m)(15)²

450 = [1/2](m)(15)²

900 = 225 m

Mass of shot (m) = 4 kg

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Answer:

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We are given;

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Explanation:

It is known that relation between torque and angular acceleration is as follows.

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So,      I_{1} = 2 kg \times (1 m)^{2} + 2 kg \times (1 m)^{2}

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     \tau_{2} = I_{2} \alpha_{2}

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