<span>CO2 (carbon) is the main product that results from burning paper. The paper is the reactant
When paper burns in a fire, the reactants are mostly carbon (the main substance in the paper) and oxygen (from the air).Co2
If paper is loaded with CaCO3 such as cigarette paper, CaCO3 decompose in to CaO and CO2</span>
Answer:
- a) 2N₂O(g) → 2N₂(g) + O₂(g)
Explanation:
Arrange the equations in the proper way for better understanding.
T<em>he reaction between nitrogen and oxygen is given below:</em>
<em />
- <em>2N₂(g) + O₂(g) → 2N₂O(g)</em>
<em />
<em>We therefore know that which of the following reactions can also occur?</em>
<em />
- <em>a) 2N₂O(g) → 2N₂(g) + O₂(g)</em>
- <em>b) N₂(g) + 2O₂(g) → 2NO₂(g)</em>
- <em>c) 2NO₂(g) → N₂(g) + 2O₂(g)</em>
- <em>d) None of the Above</em>
<h2>Solution</h2>
Notice that the first equation, a) 2N₂O(g) → 2N₂(g) + O₂(g), is the reverse of the original equation, 2N₂(g) + O₂(g) → 2N₂O(g).
The reactions in gaseous phase are reversible reactions that can be driven to one or other direction by modifying the conditions of temperature or pressure.
Thus, the equilibrium equation would be:
Which shows that both the forward and the reverse reactions occur.
Whether one or the other are favored would depend on the temperature and pressure: high temperatures would favor the reaction that consumes more heat (the endothermic reaction) and high pressures would favor the reaction that consumes more moles.
Thus, by knowing that one of the reactions can occur you can conclude that the reverse reaction can also occur.
Answer:
400 or 4x102 indicates only onesignificant figure. (To indicate that the trailing zeros are significant a decimal point must be added. 400. has threesignificant digits and is written as 4.00x102 in scientific notation.) Exact numbers have an infinite number of significant digits but they are generally not reported.
1 part per million is the same as
<span>1 mcg/mL (mcg = 1 micro gram = 1 * 10^-6 grams). </span>
<span>125 ppm = 125 mcg/mL </span>
<span>125 mcg/ml * [1 gram / 1 * 10^6 mgrm] = 1.25 * 10^-4 grams </span>
<span>The density of hard water is 1.000 grams / mL </span>
<span>50 mL of water contains 1.25 * 10^-4 grams. </span>
<span>given mass = 1.25 * 10^-4 </span>
<span>Molar mass = 100.0 grams / mole </span>
<span>n = ????? </span>
<span>n = 1.25 * 10^-4/100 = 1.25 * 10^-6 moles.
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
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Answer:
- Ideal Gas is ur answer to the question
<h3>Hope this helps you XD ✌️</h3>
