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FromTheMoon [43]
3 years ago
10

An individual unit of copper in the previous question is a(n) __________.

Chemistry
1 answer:
inysia [295]3 years ago
6 0

Explanation:

plz follow me plzzzzzzzzzzzzzzzzzzzzzzzzzzz

You might be interested in
A compound is 53. 31% c, 11. 18% h, and 35. 51% o by mass. What is its empirical formula? insert subscripts as needed.
lyudmila [28]

Answer:

C2H5O

Explanation:

In a 100 g sample we would have

53.31 g of C

11.18g of H

35.51g of O

First, we find the relative number of atoms of each element by dividing the number of grams the element has in the compound by its atomic mass.

Atomic mass of carbon is 12.011

Relative number of carbon atoms = 53.31 / 12.011 = 4.4

Atomic mass of hydrogen = 1.007

Relative number of hydrogen atoms : 11.18/1.007 = 11.1

Atomic mass of oxygen : 15.999

Relative number of oxygen atoms : 35.51 / 15.999 = 2.2


Now we find a ratio of the relative number of atoms by dividing the # of relative atoms of each element by the element's relative number of atoms that had the lowest number. ( oxygen which had 2.2 ) The outcome of each will be the subscript or number of atoms of each element.

Carbon : 4.4 / 2.2 = 2

Hydrogen : 11.1 / 2.2 = 5

Oxygen : 2.2 / 2.2 = 1

The answer is C2H5O

8 0
2 years ago
Suppose the concentration of the standard stock solution is 50.04 ppm and that you delivered 4.60 mL of this standard stock solu
12345 [234]

Answer:

9.21 ppm

Explanation:

Considering

concentration_{working\ solution}\times Volume_{working\ solution}=concentration_{stock\ solution}\times Volume_{stock\ solution}

Given  that:

concentration_{working\ solution}=?

Volume_{working\ solution}=25.00mL

Volume_{stock\ solution}=4.60mL

concentration_{stock\ solution}=50.04 ppm

So,  

concentration_{working\ solution}\times 25.00mL=50.04 ppm\times 4.60mL

concentration_{working\ solution}=\frac{50.04\times 4.60}{25.00}\ ppm=9.21\ ppm

4 0
2 years ago
A certain weak acid, ha, has a ka value of 3.6×10−7. part a calculate the percent ionization of ha in a 0.10 m solution. express
slega [8]
Answer is: <span>the percent ionization is 0,19%.
</span>Chemical reaction: HA(aq) ⇄ H⁺(aq) + A⁻(aq).
Ka(HA) = 3,6·10⁻⁷.
c(HA) = 0,1 M.
[H⁺] = [A⁻] = x; equilibrium concentration.
[HA] = 0,1 M - x.
Ka = [H⁺] · [A⁻] / [HA].
0,00000036 = x² / 0,1 M - x.
Solve quadratic equation: x = 0,00019 M.
α = 0,00019 M ÷ 0,1 M · 100% = 0,19%.
8 0
3 years ago
Which of the following would dissolve in water, and why?
Oduvanchick [21]

Answer:

It should be acetic acid.

Explanation:

When you have ionic bonds, the ionic bonds will always be water soluble; the polarity doesn't matter for this case.

4 0
3 years ago
Which of the following represents the least number of molecues?
Mars2501 [29]

Answer:

Answer: a) 20g of H2O (18.02 g/mol) molecules=6.68x10^23

Explanation:

In order to find the amount of molecules of each of the options, we need to follow the following equation.

molecules=\frac{mass(g)x6.022x10^{23}(molecules/mol) }{atomic weight(g/mol)}

So, let´s get the number of molecules for each of the options.

a) molecules=\frac{20(g)x6.022x10^{23}(molecules/mol) }{18.02(g/mol)}=6.68x10^{23}molecules

b) molecules=\frac{77(g)x6.022x10^{23}(molecules/mol) }{16.06(g/mol)}=2.89x10^{24}molecules

c) molecules=\frac{68(g)x6.022x10^{23}(molecules/mol) }{42.09(g/mol)}=9.73x10^{23}molecules

d) molecules=\frac{100(g)x6.022x10^{23}(molecules/mol) }{44.02(g/mol)}=1.37x10^{24}molecules

d) molecules=\frac{84(g)x6.022x10^{23}(molecules/mol) }{20.01(g/mol)}=2.53x10^{24}molecules

the smalest number is in option a)

Best of luck.

7 0
2 years ago
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