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LUCKY_DIMON [66]
3 years ago
13

Which statement is true about the relationship between entropy and spontaneity? O Spontaneous reactions tend to lead to higher e

ntropy. O Entropy is the same as spontaneity. As entropy increases, spontaneity decreases. o As entropy increases, spontaneity is unaffected. nics?
Chemistry
1 answer:
dimulka [17.4K]3 years ago
3 0

Answer:

The true statement is: Spontaneous reactions tend to lead to higher entropy.

Explanation:

The spontaneity of a reaction is linked to the value of Gibbs free energy (ΔG°). The more negative is this value, the more spontaneous is a reaction. At the same time, Gibbs free energy depends on enthalpy (ΔH°) and entropy (ΔS°), according to the following expression:

ΔG° = ΔH° - T.ΔS°

We can see that higher entropies (higher ΔS°) lead to more negative ΔG°, thus, more spontaneous reactions.

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Typical "hard" water contains about 2.0 x 10–3 mol of Ca2+ per liter. Calculate the maximum concentration of fluoride ion that c
malfutka [58]

Answer:

[F^-]_{max}=4x10{-3}\frac{molF^-}{L}

Explanation:

Hello,

In this case, for the described situation, we infer that calcium reacts with fluoride ions to yield insoluble calcium fluoride as shown below:

Ca^{+2}(aq)+2F^-(aq)\rightleftharpoons CaF_2(s)

Which is typically an equilibrium reaction, since calcium fluoride is able to come back to the ions. In such a way, since the maximum amount is computed via stoichiometry, we can see a 1:2 mole ratio between the ions, therefore, the required maximum amount of fluoride ions in the "hard" water (assuming no other ions) turns out:

[F^-]_{max}=2.0x10^{-3}\frac{molCa^{2+}}{L}*\frac{2molF^-}{1molCa^{2+}}  \\

[F^-]_{max}=4x10{-3}\frac{molF^-}{L}

Best regards.

8 0
3 years ago
Element X is more reactive than lithium and magnesium but less reactive than potassium. Which element is most likely to be X?
PilotLPTM [1.2K]

Answer:

It is Likely to Be Sodium (Na) coz as You Down The group the reactivity increase

3 0
3 years ago
When the energy is removed what will happen to a gas?
creativ13 [48]

Answer:

  • <u>Hey </u><u>mate </u>
  • <u>I </u><u>hope </u><u>it </u><u>helps </u>

Explanation:

<h3>Removing Energy: Removing energy will cause the particles in a liquid to begin locking into place. A. Boiling and Evaporation: Evaporation is the change of a substance from a liquid to a gas. Boiling is the change of a liquid to a vapor, or gas, throughout the liquid.</h3>

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8 0
3 years ago
Read 2 more answers
15g of magnesium (II) oxide decomposes, find the number of oxygen particles produced at 100% yield.
erastova [34]

2.258625 *10²³ oxygen atoms will be produced.

<h3><u>Explanation:</u></h3>

Decomposition reaction is defined as the type of reaction where one single reactant breaks to produce more than one product only by means of heat or other external factor.

Formula of magnesium oxide = MgO.

The molecular mass of magnesium oxide = 24 +16= 40.

So in 40 grams of magnesium oxide, number of molecules is 6.023 * 10²³.

So in 15 grams of magnesium oxide,, number of molecules is 6.023 *1023 * 15/40 = 2.258625 *10²³.

From one molecule of magnesium oxide, one oxide atom will be produced.

So number of oxide atoms with 100% yeild = 2.258625 *10²³

6 0
3 years ago
Consider the following reaction: 2{\rm{ N}}_2 {\rm{O(}}g)\; \rightarrow \;2{\rm{ N}}_2 (g)\; + \;{\rm{O}}_2 (g)
fredd [130]

Answer:

a. 5.9 × 10⁻³ M/s

b. 0.012 M/s

Explanation:

Let's consider the following reaction.

2 N₂O(g) → 2 N₂(g) + O₂(g)

a.

Time (t): 12.0 s

Δn(O₂): 1.7 × 10⁻² mol

Volume (V): 0.240 L

We can find the average rate of the reaction over this time interval using the following expression.

r = Δn(O₂) / V × t

r = 1.7 × 10⁻² mol / 0.240 L × 12.0 s

r = 5.9 × 10⁻³ M/s

b. The molar ratio of N₂O to O₂ is 2:1. The rate of change of N₂O is:

5.9 × 10⁻³ mol O₂/L.s × (2 mol N₂O/1 mol O₂) = 0.012 M/s

4 0
3 years ago
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