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3 years ago

Which statement about the total velocity of a projectile launched at an angle less than 90° above a flat surface is true?

Physics

2 answers:

Veseljchak [2.6K]3 years ago

5 0

Hello Darkfyre97,

My name is Rendorforestmusic and I am here to help!

Your question states: Which statement about the total velocity of a projectile launched at an angle less than 90° above a flat surface is true?

Your answer would be: B.

The total velocity is equal at launch and at landing.

Explanation: As the projectile goes up it increases it’s speed and as it reaches its highest point it will reach zero.

Brainliest!?!

Hope this helps!

Have a great day:)

~Rendorforestmusic

marissa [1.9K]3 years ago

3 0

The correct answer is B the total velocity is equal at both landing and launch because before your about launch you have 0 velocity then when you have landed you also have 0 velocity. Hope This Helps

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Answer:

241.7 s

Explanation:

We are given that

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$2.74\times 10^{-6}V_1=6.65\times 10^{-10} J$

$V_1=\frac{6.65\times 10^{-10}}{2.74\times 10^{-6}}=2.43\times 10^{-4} V$

Initial voltage= $V_1=2.43\times 10^{-4} V$

$\frac{\initial\;voltage}{final\;voltage}=(\frac{initial\;time}{final\;time})^2$

Using the formula

$\frac{V_1}{V_2}=(\frac{6.36}{t})^2$

$\frac{2.43\times 10^{-4}}{0.351}=\frac{(6.36)^2}{t^2}$

$t^2=\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}$

$t=\sqrt{\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}}$

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Answer:

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Explanation:

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Calculating the acceleration using one of Newton's equations of motion:

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Note: The negative sign denotes deceleration.

When speed, v = 79mi/h, the acceleration is equal to when it is 44mi/h i.e. -116206.48 mi/h^2

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