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Marrrta [24]
3 years ago
10

A rotating wheel requires a time Δt = [01]_____________________ to rotate 37.0 revolutions. Its angular speed at the end of the

interval is ω = 75.9 rad/s. What is the constant angular acceleration (rad/s2 ) of the wheel
Physics
1 answer:
Sidana [21]3 years ago
8 0

Answer:

Explanation:

Initial angular velocity ω₁ = 0 , final angular velocity ω₂ = 75.9 rad /s

angle rotated =  θ

= 37 x 2π

= 74 π

The formula for angular velocity

ω₂² =  ω₁² + 2αθ , α is angular acceleration

75.9² = 0 + 2 α x 74 π

α = 75.9² / 2  x 74 π

= 12.396 rad / s²

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Question: Point B is 25 km due east of point A. Starting from point A, a camel walks 20 km in
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<em>Resultant angle; θ = 25.59°  </em>

This question is dealing with bearings and distance.

We are told that from point A, the camel walks 20 km at 15° in the south of east direction.

Thus, d_s,e = 20 km

Resolving along the horizontal east direction gives; d_e = 20 cos 15

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Also, resolving along the vertical south direction gives; d_s = 20 sin 15

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Now, the resultant angle is given by;

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tan θ = 0.4789

θ = tan^(-1) 0.4789

θ = 25.59°

Read more at; brainly.com/question/22518031

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