The sphere’s Electric potential energy is 1.6*
J
Given,
q=6. 5 µc, V=240 v,
We know that sphere’s Electric potential energy(E) = qV=6.5*
=1.6*J
<h3>Electric potential energy</h3>
The configuration of a certain set of point charges within a given system is connected with the potential energy (measured in joules) known as electric potential energy, which is a product of conservative Coulomb forces. Two crucial factors—its inherent electric charge and its position in relation to other electrically charged objects—can determine whether an object has electric potential energy.
In systems with time-varying electric fields, the potential energy is referred to as "electric potential energy," but in systems with time-invariant electric fields, the potential energy is referred to as "electrostatic potential energy."
A tiny sphere carrying a charge of 6. 5 µc sits in an electric field, at a point where the electric potential is 240 v. what is the sphere’s potential energy?
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Answer:
Because the wavelengths of macroscopic objects are too short for them to be detectable.
Explanation:
Wavelength of an object is given by de Broglie wavelength as:
Where, 'h' is Planck's constant, 'm' is mass of object and 'v' is its velocity.
So, for macroscopic objects, the mass is very large compared to microscopic objects. As we can observe from the above formula, there is an inverse relationship between the mass and wavelength of the object.
So, for vary larger masses, the wavelength would be too short and one will find it undetectable. Therefore, we don't observe wave properties in macroscopic objects.
From the given information:
- Taking the movement of the Duck in the North as the x-direction
- The movement of the Duck in the East direction as the y-direction
However, we will have to compute the initial velocity and the acceleration of the duck in their vector forms.
<h3>In vector form;</h3>
The initial velocity is:
The acceleration is:
The objective of this question is to determine the speed of the duck at a certain time. Since it is not given, let's assume we are to determine the Duck speed after 4 seconds of accelerating;
Then, it implies that time (t) = 4 seconds.
Using the first equation of motion:
Then, we can replace their values into the equation of motion in order to determine the speed:
Collect like terms:
Thus, the magnitude is:
Therefore, we can conclude that the speed of the duck after 4 seconds is 1.34 m/s
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Answer:
a. 28.27 m/s
b. 12.75 m/s
c. No
Explanation:
a.
The bottom
Ek = Ep
¹/₂ * m * v² = m * g * h₁
v = √ 2 * g * h₁ = √ 2 * 9.8 * 40.8 m
v = 28.27 m/s
b.
At the top
Ek = Ep
¹/₂ * m * v² = m * g * h₁
v = √ 2 * g * h₁ = √ 2 * 9.8 * (40.8 - 32.5) m
v = 12.75 m/s
c.
No in this case the axis is the same of the motion so, the angle doesn't affect the result
