Answer:
The speed of space station floor is 49.49 m/s.
Explanation:
Given that,
Mass of astronaut = 56 kg
Radius = 250 m
We need to calculate the speed of space station floor
Using centripetal force and newton's second law
Where, v = speed of space station floor
r = radius
g = acceleration due to gravity
Put the value into the formula
Hence, The speed of space station floor is 49.49 m/s.
Fahrenheit because the boiling point of water is 100 degrees Celsius which is 212 Fahrenheit which is very hot, and that would be about 200 Kelvin so therefore the answer is that the temperature was recorded in Fahrenheit not Kelvin or Celsius
Answer:the resistance decrease
Explanation:
Answer:
Explanation:
Given that,
The length of a simple pendulum, l = 2.2 m
The time period of oscillations, T = 4.8 s
We need to find the surface gravity of the planet. The time period of the planet is given by the relation as follows :
Put all the values,
So, the value of the surface gravity of the planet is equal to 
.
