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sdas [7]
3 years ago
11

How do you graph motion in physics? How do you graph motion in physics? I've seen problems state that an object is in free fall

or that it was thrown upward and hits the ground, but I don't know how to graph them. If acceleration is gravity, I know that -9.8 should be in the equation somewhere, but I don't know how to incorporate that number with an initial velocity and height.
Physics
1 answer:
Dahasolnce [82]3 years ago
5 0

This is Kinematics and the equations in your book.

A speed time graph would plot the speed of something against the teime it was at a speed.

If it were changing it speed constantly, that would be a straight line if acclerating. Total distrance would be the area under the graph.

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Classical conditioning requires _____.
LekaFEV [45]
I would say A classical conditioning definitely demands a pairing of two stimuli
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5 0
3 years ago
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The terminal speed of a sky diver is 130 km/h in the spread-eagle position and 326 km/h in the nosedive position. Assuming that
SIZIF [17.4K]

Answer:

\frac{A_{slow} }{A_{fast} }=6.2885

Explanation:

Given data

Terminal velocity for spread eagle position vt=130 km/h

Terminal velocity for nosedive position vt=326 km/h

The terminal speed of the diver is given by

v_{t}=\sqrt{\frac{2mg}{CpA} }

Therefore the area is given by

A=\frac{2mg}{Cp(v_{t})^{2}  }\\

Since everything else is constant in the two dives except for the terminal velocity, the ratio between the area in the slow position to the area in the fast position is

\frac{A_{slow} }{A_{fast} }=\frac{326^{2} }{130^{2} }\\\frac{A_{slow} }{A_{fast} }=6.2885

8 0
3 years ago
Why does Quito, Equator has very little changes to the daylight hours<br> throughout the year?
marin [14]

Because of the position on the equator, the change in rotation of the Earth on its axis throughout the year doesn't affect it much. Unlike the poles, Quito is almost constantly in direct view of the sun. So, because of lack of change in rotation, the daylight hours are hardly varied as Quito is almost constantly in more or less the same spot in relation to the sun.

4 0
3 years ago
Reply quick pls
Sholpan [36]
The ball was moving for 0.8seconds
This is because 4/5 x 1 = 0.8

Hope this helps and good luckkkk :)
4 0
2 years ago
7. What is the velocity of an object with a distance of 90m south and a time of<br> 5s?
IrinaK [193]

Answer:

Explanation:

v= s/t

V =90m/5s

V = 8m/s

4 0
2 years ago
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