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Svetach [21]
2 years ago
8

Which of the following is a correct definition of the word "contingencies"?

Physics
1 answer:
Elden [556K]2 years ago
3 0

Answer:

I already told ya

Explanation:

i got brainly so i could learn

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How do u convert 7.68 cal/sec to kcal/min
stich3 [128]
<span>First you have to convert 7.68 cal/sec to cal/min to do that, just multiply by 60 So it will be 460.8 cal/min now convert that to kcal/min kcal = kilocalories = 1000 calories. so just divide by 1000 and youll have your answer in kcal/min </span>
5 0
4 years ago
Read 2 more answers
Very small particles moving in viscous fluids experience a drag force proportional to
Likurg_2 [28]

Answer:

t = 3w/gk

y = w²/gk²(2+e^-gkt/t)

Explanation:

The detailed step by step solution can be found in the attachment below.

Vt = W/k. It is the velocity of the body when the drag force = the weight of the particle.

I steps have been explaine6in the attachments below.

3 0
3 years ago
On a spending spree in Malaysia, you buy an ox with a weight of 28.9 piculs in the local unit of weights: 1 picul = 100 gins, 1
Talja [164]

Answer:

1747.41 kg

Explanation:

If          1 piculs = 100 gins,

Then     28.9 piculs = (28.9 × 100) gins = 2890 gins.

Also,

If         1 gin = 16 tahils

then   2890 gins =( 16 × 2890 ) = 46240 tahils

Also,

If         1 tahil = 10 chees,

Then    46240 tahils = 46240 × 10 chees = 462400 chees.

Also,

If           1 chee = 10 hoons

Then      462400 chees =( 10 × 462400) hoons = 4624000 hoons.

Also,

If            1 hoon = 0.3779 g,

Then     4624000 hoons = 0.3779 × 4624000 = 1747409.6 g.

The mass in kg that i will declare in the shipping manifest = (1747409.6/100 )kg = 1747.41 kg

6 0
3 years ago
Which characteristic of water allows its molecules to form hydrogen bonds? The water molecule is polar. Water has a low specific
Fittoniya [83]
Definitely the first: the water molecule is polar. :)
5 0
3 years ago
Read 2 more answers
Free charges do not remain stationary when close together. To illustrate this, calculate the magnitude of the instantaneous acce
ASHA 777 [7]

Answer:

a=2.304×10¹⁶m/s²

Explanation:

Given data

Distance d=2.5 nm=2,5×10⁻⁹m

Mass of proton m=1.6×10⁻²⁷kg

charge of proton q=1.6×10⁻¹⁹C

To find

acceleration a

Solution

Apply the Coulombs Law

F=k\frac{q_{1}q_{2}  }{r^{2} }

Where k is coulombs constant (k=9×10⁹Nm²/C²)

q=q₁=q₂

r=d

So

F=k\frac{|q^{2} |}{d^{2} }\\ as \\F=ma\\ma=k\frac{|q^{2} |}{d^{2} }\\a=\frac{k}{m} \frac{|q^{2} |}{d^{2} }\\a=\frac{(9*10^{9} )*(1.6*10^{-19} )^{2} }{(1.6*10^{-27} )*(2.5*10^{-9} )^{2} }\\ a=2.304*10^{16}m/s^{2}  

4 0
4 years ago
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