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Svetach [21]
2 years ago
8

Which of the following is a correct definition of the word "contingencies"?

Physics
1 answer:
Elden [556K]2 years ago
3 0

Answer:

I already told ya

Explanation:

i got brainly so i could learn

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I need this done by tonight!! Can anyone help me please? Answer these 4 questions
VikaD [51]

Answer:

1. 14 g of chocolate mixture.

2. 24 fl oz of chocolate milk

3. 10 cups of chocolate milk.

4. 12½ cups.

Explanation:

From the question given above, the following data were obtained:

1 TBSP = 7 g

1 Cup = 8 fl oz

2 Table spoons (TBSP) for 1 cup (8 fl oz) of milk.

1. Determination of the mass of chocolate mixture in 1 cup of chocolate milk.

From the question given above,

1 Cup required 2 Table spoons (TBSP)

But

1 TBSP = 7 g

Therefore,

2 TBSP = 2 × 7 = 14 g

Thus, 1 Cup required 14 g of chocolate mixture.

2. Determination of the number fl oz of chocolate milk in 3 cups

1 Cup = 8 fl oz

Therefore,

3 Cups = 3 × 8

3 Cups = 24 fl oz

Thus, 24 fl oz of chocolate milk are in 3 cups.

3. Determination of the number of cups of chocolate milk produce from 20 TBSP.

2 TBSP is required to produce 1 cup.

Therefore,

20 TBSP will produce = 20/2 = 10 Cups.

Thus, 10 cups of chocolate milk produce from 20 TBSP.

4. Determination of the number of cups obtained from 100 fl oz chocolate milk.

8 fl oz is required to produce 1 cup.

Therefore,

100 fl oz will produce = 100 / 8 = 12½ cups.

Thus, 12½ cups is obtained from 100 fl oz chocolate milk.

4 0
3 years ago
A team of scientists is studying an earthquake. Which task would the physical scientist most likely do?
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They might use a seismometer
7 0
3 years ago
It takes 200 J of work to compress quasi-statically 0.40 mol of an ideal gas to one-fourth its original volume. Calculate the te
mario62 [17]

Answer : The temperature of the gas is, 43.4 K

Explanation :

The expression used for work done will be,

w=-nRT\ln (\frac{V_2}{V_1})

where,

w = work done = 200 J

n = number of moles of gas  = 0.40 mol

R = gas constant = 8.314 J/mole K

T = temperature of gas  = ?

V_1 = initial volume of gas  = X

V_2 = final volume of gas  = \frac{X}{4}

Now put all the given values in the above formula, we get :

200J=-0.40mol\times 8.314J/moleK\times T\times \ln (\frac{(\frac{X}{4})}{X})

T=43.4K

Thus, the temperature of the gas is, 43.4 K

3 0
4 years ago
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