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ad-work [718]
3 years ago
9

A living cell with a tonicity (solute concentration) equivalent to 0.9% NaCl is placed in a solution containing 2% NaCl. Assume

that aquaporins are present and that the membrane therefore is permeable to water.
Chemistry
1 answer:
Stells [14]3 years ago
4 0

Answer:

This question is incomplete

Explanation:

This illustration refers to an hypertonic solution. Hypertonic solution is a solution in which the surrounding solution has a higher solute concentration (2% of NaCl) than the cell's cytosol (0.9% of NaCl). In hypertonic solution, the solution outside the cell (with higher concentration) pulls the water from the cell's cytosol (via osmosis) causing the cell to shrink.

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What is the difference between a polar and a nonpolar bond?And how can i figure out if its polar or nonpolar in a bond question?
ra1l [238]

Answer:

If the electronegativity of two atoms is basically the same, a nonpolar covalent bond will form, and if the electronegativity is slightly different, a polar covalent bond will form.

Explanation:

that's your answer very easy.

5 0
3 years ago
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Pure substance uniform
Lerok [7]
What? there isn’t a question here
6 0
3 years ago
What particle is emitted when lead-214, 214 82 pb undergoes natural radioactive decay to bismuth-214, 214 83 bi?
const2013 [10]
A beta particle.<span>β
</span> Looking at the particles before and after for the decay, you'll see that there is a total of 214 neutrons and protons both before and after the radioactive decay. But you'll also see that before the decay, there were 82 protons and after the decay, there are 83 protons. So a neutron was converted to a proton which means that a negative charge had to be emitted, so it's a beta decay where a neutron emits a beta particle (an electron). The beta particle can be represented as a greek beta <span>β</span> followed by a minus sign, giving β-, or as a "e" followed by a minus sign, so e-
6 0
3 years ago
A 10.00 g sample of a compound containing only carbon, hydrogen, and oxygen forms 23.98 g CO2 and 4.91 g H2O upon complete combu
yanalaym [24]
We can determine the empirical formula by first converting each of the grams to moles. remember to do this, first, we need the molar mass of the molecules which can be calculated by adding the mass of the atoms from the periodic table. 

molar mass of CO2= 44.0 g/mol
molar mass of H2O= 18.02 g/mol

now, lets determine the grams of each atom

Carbon: 23.98 g x (12.011 g / 44.01 g) = 6.54 g C

Hydrogen: 4.91 g x (2.0158 g / 18.02 g) = 0.55 g H

Oxygen: 10.0 - (6.54 + 0.55) = 2.91 g O

Now let's convert each mass to moles.

C: 6.54 g / 12.01 g / mol = 0.54 mol
H: 0.55 g / 1.01 g/mol = 0.54 mol
O: 2.91 g / 16.00 g/mol = 0.18 mol

now that we have the moles of each atom, we need to divide them by the smallest value to find the ration. If you do not get the whole number, you need to multiply until to get a whole number.

C:  0.54 mol / 0.18 mol = 3
H:  0.54 mol / 0.18 mol = 3
O: 0.18 mol / 0.18 mol = 1

empirical formula--> C₃H₃O



4 0
4 years ago
Calculate the molarity when 135 g of KCl is dissolved to make a 2.50 L solution. Round to two significant digits.
inysia [295]
<h2>0.72 mol/L</h2>

Explanation:

       \textrm{Molarity of a solution}=\frac{\textrm{Number of moles of solvent}}{\textrm{Volume of solution in Liters}}

       We are given a 2.50L solution which contains 135g of KCl.

       To calculate number of moles of KCl present, we need to find it's molar mass from charts. Molar Mass of KCl is known to be 74.55\frac{g}{Mol}.

       Number of moles of KCl present = \frac{\textrm{Given weight}}{\textrm{Molar Mass}}\textrm{ = }\frac{135g}{74.55\frac{g}{Mol}}\textrm{ = }1.81087mol

       Molarity = \frac{1.81087mol}{2.50L}=0.7243\frac{mol}{L}

∴ Molarity of given KCl solution = 0.72\frac{mol}{L}

7 0
3 years ago
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