Question

3

Answer 1

Answer: 0.0450 moles of $CaCl_2$

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles of} CaCl_2=\frac{5.00g}{110.98g/mol}=0.0450moles$

Thus there are 0.0450 moles of $CaCl_2$