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3 years ago

A 9.0 mL sample of oxygen gas (Q) is stored at a pressure of 6.3 atm. If the pressure of the sample

Chemistry

1 answer:

Julli [10]3 years ago

6 0

Answer:

<h2>The answer is 23.63 mL</h2>

Explanation:

In order to find the new volume we use the formula for Boyle's law which is

$P_1V_1 = P_2V_2 \\$

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the new volume

$V_2 = \frac{P_1V_1}{P_2} \\$

From the question

P1 = 6.3 atm

V1 = 9 mL

P2 = 2.4 atm

So we have

$V_2 = \frac{6.3 \times 9}{2.4} \\ = 23.625$

We have the final answer as

Hope this helps you

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What is the correct interpretation of the mole ratios for the elements in

VLD [36.1K]

Answer:

6 moles of C atoms, 12 moles of H atoms and 6 moles of O atoms

Explanation:

A chemical formula represents the number of moles of atoms presents in 1 mole of the compound.

For example, for 1 mole:

CₐHₓ, you have a moles of carbon and x moles of hydrogen.

Thus, for the molecule:

C₆H₁₂O₆, you have <em>6 moles of C atoms, 12 moles of H atoms and 6 moles of O atoms</em>

6 0

3 years ago

Can anyone help with thiss??

IrinaVladis [17]

l
kg
cm
gm
ml
km,m
m
nm
mg
ms
gm
nm
.
.
l,gm
.
kg
m
gm,m
s

Hope this helps :-). And....

ml: milliliter

kg: kilogram

m: meter

mg: milligram

mm: millimeter

ms: millisecond

l: liter

km: kilometer

µg: micro gram

cm: centimeter

g: gram

nm: nano meter

5 0

3 years ago

Can you use molecular orbital theory to explain why fluorine is such a highly reactive gas?

vivado [14]

The F2 molecular orbital diagram shows 4e- are in the highest energy antibonding (destabilizing) molecular orbitals resulting in a bond order = 1.

Single bonds are easier to break and therefore more reactive. So the answer is yes.

7 0

3 years ago

Refer to your periodic table:

Mazyrski [523]

iondine

Explanation:

bromine has 185pm, astatine haa 200, iondine has 140 and lastly fluorine has 147. so iondine has the smallest atomic radius

6 0

3 years ago

In a series circuit there are 17 light bulbs, each providing 1 ohm of resistance. What is the total resistance?

Sauron [17]

Answer:

17 ohms

Explanation:

Given that,

In a series circuit there are 17 light bulbs, each providing 1 ohm of resistance.

We need to find the total resistance of the circuit.

The equivalent resistance for series combination is given by :

$R_{eq}=R_1+R_2+....$

For 17 light bulbs, the equivalent resistance is given by :

$R_{eq}=R+R+....\text{upto 17 terms}\\\\R_{eq}=17R\\\\=17$

Hence, the total resistance is 17 ohms. Hence, the correct option is (d).

7 0

3 years ago