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mr Goodwill [35]
3 years ago
9

A biologist wants to increase the rate of his chemical reaction but has a limited amount of enzyme. He continues to increases th

e substrate concentration instead. Eventually, the reaction rate levels off, and he can't get it to go any faster. What prevented the rate from increasing further?
Chemistry
1 answer:
Nadya [2.5K]3 years ago
5 0

Answer: The enzyme has effectively becomes saturated.

Explanation:

Increasing substrate concentration increases the reaction rate this is because more substrate molecules will collide with enzymes molecules so more product will be formed, but at a point any increase in concentration will have no effect on the rate of reaction because substrate concentration will no longer be the limiting factor.

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What is the average atomic mass of an element that has 3 isotopes with the data below?
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Answer:

How do you calculate the average atomic mass of three isotopes?

To calculate the average atomic mass, multiply the fraction by the mass number for each isotope, then add them together. Whenever we do mass calculations involving elements or compounds (combinations of elements), we always use average atomic masses

Explanation:

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The element found naturally in the earth that has the heights atomic number is
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The element found naturally in the earth , that has the highest atomic number is 7

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Why black body rodiat​
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Because it has a darker pigment?

Explanation:

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3 years ago
sam records the mass of his evaporating dish as 8.365 g. he records the mass of the evaporating dish and the sample of hydrate a
guapka [62]

0.2701 moles of water were evaporated from the sample by the heating process

Mass of evaporating dish = 8.365 g

mass of dish + hydrate = 18.597 g

mass of hydrate =  (mass of dish + hydrate) - mass of dish

hydrate = 18.597 - 8.365 = 10.232 g

Mass of dehydrated material = (mass of dish + dehydrate ) - mass of dish

dehydrated material = 18.735 - 8.365 = 5.37 g

Mass of water evaporated = hydrate - dehydrate

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brainly.com/question/29367909

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7 0
1 year ago
By weight atmospheric air is approximately 23.15% oxygen and 76.85% nitrogen. What is the partial pressure of oxygen in the air
inna [77]

Answer:

Partial pressure of oxygen = 23.38 kpa (Approx)

Explanation:

Given:

Amount of oxygen = 23.15%

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Pressure (missing) = 101 kpa

Find:

Partial pressure of oxygen

Computation:

Partial pressure of oxygen = [Amount of oxygen x Pressure]/100

Partial pressure of oxygen = [23.15% x 101]/100

Partial pressure of oxygen = 23.38 kpa (Approx)

5 0
3 years ago
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