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neonofarm [45]
3 years ago
6

Which of the following quantum number combinations is not allowed in an atom?

Chemistry
2 answers:
marysya [2.9K]3 years ago
8 0
The fourth combination is not allowed.


The third quantum number, i.e. m subscript l, only may an integer number from -l to + l. Given that l = 0, the only allowed m subscript l is 0.
nika2105 [10]3 years ago
5 0

The answer is n = 1, l = 0, m subscript l = 1

The 4 quantum numbers of the electronic configuration

n: main quantum number. It defines the layer.

n = 1 at layer K

n = 2 at layer L

n = 3 at layer M

And so on…

The energy of the electron is a function of n.

l: secondary or azimuth quantum number

it is an integer that varies from 0 to n-1. It defines the sub-layers s, p, d, f

l = 0 under layer s

l = 1 under layer  p

l = 2 under layer d

l = 3 under layer f

It defines the shape and symmetry of the orbitals (orbital s, p, d etc ...)

Example n = 2 to l = 0 or l = 1 from which 2 sublayers 1s and 2p

m: magnetic quantum number

It takes values ​​between -l and l (including the values ​​of -l and l). At a value of m, correspond to 2l + 1 value of m. It determines the orbital orientation in space (see the shape of the orbitals.

s: quantum number of spin

The quantum number of spin is defined as the kinetic moment (or angular momentum) of the electron. s = -1 / 2 or ½ (2 directions of rotation of the electron on itself)

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List the specific sources of non renewable energy used in 2006
blsea [12.9K]

A list of specific sources of non renewable energy used in 2006 are

- Petroleum[these are natural gases and oils] (28%)

-  Natural gases (31.8%)

- coal (17.8%)

8 0
3 years ago
Help with this question I don’t get it I will give out 30 points!!!
Paladinen [302]

Answer: The second choice

Explanation: The question is most likely asking what the arrow's pointing at, and it's right at the meeting point for lines x and y. Lines x and y would be the common ancestors of the point the arrow is showing since they're above the point and meet up to the point.

7 0
2 years ago
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You need to make an aqueous solution of 0.243 M iron(III) chloride for an experiment in lab, using a 125 mL volumetric flask. Ho
irakobra [83]

Answer:

5 g

Explanation:

From the question, we have,

Molarity of FeIII solution= 0.245 M

Volume of solution = 125 ml

From

number of moles= concentration × volume

We have;

Number of moles= 0.245 M × 125/1000

Number of moles = 0.031 moles

Molar mass of Fe III = 162.5g/moles

Mass of iron III = number of moles× molar mass = 0.031 × 162.5= 5 g

n

3 0
3 years ago
Which of the following forms a molecular solid? Which of the following forms a molecular solid? C, graphite C10H22 CaO gold
Damm [24]

Answer:

C10H22

Explanation:

Molecular Solids comprises of a Vander waal's force of attraction between the molecule. These forces are very weak when compared to ionic and covalent bond.

In Carbon, Carbon is not a molecule but an atom. One of it unique characteristics is that it forms bonds with other carbon atoms. This property is know as catenation. The bond between these carbon atoms is know as covalent bond.

Graphite is an allotrope of carbon. It exists as black , slippery, hexagonal crystals.The carbon atoms in graphite forms flat layers and are joined together by strong covalent bonds. Graphite can be used as lubricant in engines.

Gold (Au) is an element on the periodic table with atomic number 79 and a mass number 197. It exists as a metal. Most times Gold forms hydrogen bonds.

C10H22 is known as decane. It is the tenth compound formed in the series of alkane family( an organic unsaturated carbon chain family). Alkanes are aliphatic hydrocarbons. The forces of attraction between the alkane family are weak.In decane , their exists Vander waal's force which makes Decane C10H22 a Molecular Solid.

6 0
3 years ago
How many moles of sulfur are in 53.7 grams of sulfur?
PolarNik [594]
NO.OF.MOLES= MASS/ATOMIC MASS
THE ATOMICITY OF SULPHUR IS 8 AND ITS MASS NUMBER IS 32.
SO, THE ATOMIC MASS IS 256
NO.OF.MOLES= 53.7/256
= 537/2560
= 0.2097
6 0
2 years ago
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