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3 years ago

Which of the following quantum number combinations is not allowed in an atom?

2 answers:

8 0

The fourth combination is not allowed.

The third quantum number, i.e. m subscript l, only may an integer number from -l to + l. Given that l = 0, the only allowed m subscript l is 0.

nika2105 [10]3 years ago

5 0

The answer is n = 1, l = 0, m subscript l = 1

The 4 quantum numbers of the electronic configuration

n: main quantum number. It defines the layer.

n = 1 at layer K

n = 2 at layer L

n = 3 at layer M

And so on…

The energy of the electron is a function of n.

l: secondary or azimuth quantum number

it is an integer that varies from 0 to n-1. It defines the sub-layers s, p, d, f

l = 0 under layer s

l = 1 under layer p

l = 2 under layer d

l = 3 under layer f

It defines the shape and symmetry of the orbitals (orbital s, p, d etc ...)

Example n = 2 to l = 0 or l = 1 from which 2 sublayers 1s and 2p

m: magnetic quantum number

It takes values between -l and l (including the values of -l and l). At a value of m, correspond to 2l + 1 value of m. It determines the orbital orientation in space (see the shape of the orbitals.

s: quantum number of spin

The quantum number of spin is defined as the kinetic moment (or angular momentum) of the electron. s = -1 / 2 or ½ (2 directions of rotation of the electron on itself)

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How does evaporation lead to precipitation

Serhud [2]

Answer:

1.evaperation

2.condenstation

3.precipatation

Explanation:

So I guess condenstation leads to precipatation-

5 0

3 years ago

Read 2 more answers

Propose a mechanism for the following reaction.

raketka [301]

First, recognize that this is an elimination reaction in which hydroxide must leave and a double bond must form in its place. It is likely an E2 reaction. Here is an efficient mechanism:
1) Pre-reaction: Protonate the -OH to make it a good leaving group, water. H2SO4 or any strong H+ donor works. The water is positively charged but still connected to the compound.
2) E2: Use a sterically hindered base, such as tert-butoxide (tButO-) to abstract the hydrogen from the secondary carbon. [You want a sterically hindered base because a strong, non-sterically hindered base could also abstract a hydrogen from one of the two methyl groups on the tertiary carbon, and that leads to unwanted products, which is not efficient]. As the proton of hydrogen is abstracted, water leaves at the same time, creating an intermediate tertiary carbocation, and the 2 electrons in the C-H bond immediately are used to make a double bond towards the partial positive charge.
In the products we see the major product and water, as expected. Even though you have an intermediate, remember that an E2 mechanism technically happens in one step after -OH protonation.

5 0

3 years ago

Three chemical reactions of ethane?

Otrada [13]

Answer:

1.Hydrogenation of Alkenes and akynes.

2.Reaction of alkylhalides.

3. Halogenation.

6 0

3 years ago

Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 9.32 g of ethane is

Pie

Answer:

There will remain 8.06 grams of ethane

Explanation:

Step 1: Data given

Mass of ethane = 9.32 grams

Mass of oxygen = 12.0 grams

Molar mass ethane = 30.07 g/mol

Molar mass oxygen = 32.00 g/mol

Step 2: The balanced equation

2 C2H6 + 7 O2 → 4 CO2 + 6 H2O

Step 3: Calculate moles ethane

Moles ethane = mass ethane / molar mass ethane

Moles ethane = 9.32 grams / 30.07 g/mol

Moles ethane = 0.3099 moles

Step 4: Calculate moles oxygen

Moles oxygen = 12.0 grams / 32.0 g/mol

Moles oxygen = 0.375 moles

Step 5: Calculate the limiting reactant

For 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed ( 0.375 moles)

Ethane is in excess. There will react 2/7 * 0.375 = 0.107 moles

There will remain 0.375 - 0.107 = 0.268 moles

Step 6: Calculate mass ethane

Mass ethane = moles ethane * molar mass ethane

Mass ethane = 0.268 moles * 30.07 g/mol

Mass ethane = 8.06 grams

There will remain 8.06 grams of ethane

7 0

4 years ago

A sample of CO2 weighing 86.34g contains how many molecules?

irakobra [83]

Answer:

1.181 × 10²⁴ molecules CO₂

General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

86.34 g CO₂

Step 2: Identify Conversion

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

Step 3: Convert

$86.34 \ g \ CO_2(\frac{1 \ mol \ CO_2}{44.01 \ g \ CO_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2} )$ = 1.18141 × 10²⁴ molecules CO₂

Step 4: Check

We are given 4 sig figs. Follow sig fig rules and round.

1.18141 × 10²⁴ molecules CO₂ ≈ 1.181 × 10²⁴ molecules CO₂

4 0

3 years ago