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jasenka [17]
3 years ago
5

A ball rolls down a ramp for 15 seconds. If the initial velocity of the ball was 0.8m/s and the final velocity was 7m/s, what wa

s the acceleration of the ball?
Physics
1 answer:
iren [92.7K]3 years ago
6 0
Acceleration = (change in speed) / (time for the change)

Change in speed = (ending speed) - (starting speed)

                            =  (7.0 m/s)  -  (0.8 m/s)  =  6.2 m/s

Time for the change  =  15 seconds

Acceleration  =  (6.2 m/s) / (15 sec)

                      =   (6.2/15)  m/s²

                      =     0.413 m/s²  
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Unpolarized light passes through two polarizers whose transmission axes are at an angle # with respect to each other. What shoul
Yuki888 [10]

Answer:

63.4^{\circ}

Explanation:

When unpolarized light passes through the first polarizer, the intensity of the light is reduced by a factor 1/2, so

I_1 = \frac{1}{2}I_0 (1)

where I_0 is the intensity of the initial unpolarized light, while I_1 is the intensity of the polarized light coming out from the first filter. Light that comes out from the first polarizer is also polarized, in the same direction as the axis of the first polarizer.

When the (now polarized) light hits the second polarizer, whose axis of polarization is rotated by an angle \theta with respect to the first one, the intensity of the light coming out is

I_2 = I_1 cos^2 \theta (2)

If we combine (1) and (2) together,

I_2 = \frac{1}{2}I_0 cos^2 \theta (3)

We want the final intensity to be 1/10 the initial intensity, so

I_2 = \frac{1}{10}I_0

So we can rewrite (3) as

\frac{1}{10}I_0 =  \frac{1}{2}I_0 cos^2 \theta

From which we find

cos^2 \theta = \frac{1}{5}

cos \theta = \frac{1}{\sqrt{5}}

\theta=cos^{-1}(\frac{1}{\sqrt{5}})=63.4^{\circ}

6 0
3 years ago
2. A net force is _____.
Art [367]

The answer would be "the vector sum of forces acting on a particle or body."

Hope that helped ^^

8 0
3 years ago
A solid conducting sphere with radius R carries a positive total charge Q. The sphere is surrounded by an insulating shell with
Illusion [34]

Answer:

Explanation:

Volume of the insulating shell is,

V_{shell}=\frac{4}{3}\pi(R^3_2-R^3_1)

Charge density of the shell is,

\rho=\frac{Q_{shell}}{\frac{4}{3}\pi(R^3_2-R^3_1)}

Here, R_2 =2R, R_1 =R \,and\, Q_{shell} =-Q

\rho=\frac{Q_{shell}}{\frac{4}{3}\pi((2R)^3-R^3)}=\frac{-3Q}{28\piR^3}

B)

The electric field is E=\frac{1}{4\pi\epsilon_0}\frac{Qr}{R^3}

For 0 <r<R the electric field is zero, because the electric field inside the conductor is zero.

C)

For R <r <2R According to gauss law

E(4\pi r^2)=\frac{Q}{\epsilon_0}+\frac{4\pi\rho}{3\epsilon_0}(r^3-R^3)

substitute \rho=\frac{-3Q}{28\piR^3}

E=\frac{2}{7\pi\epsilon_0}\frac{Q}{r^2}-\frac{Qr}{28\piR^3}

D)

The net charge enclosed for each r in this range is positive and the electric field is outward

E)

For r>2R

Charge enclosed is zero, so electric field is zero

8 0
3 years ago
The moon does not have its own _____.
noname [10]
The moon does not have its own light. 
7 0
3 years ago
Read 2 more answers
If u speed up from rest to 12 m/s in 3 seconds, what is your acceleration
irakobra [83]
4

Just divide 12 by 3, so if it takes 3 seconds, then every second, it goes up 4.
4 0
3 years ago
Read 2 more answers
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