Answer:
2.4 × 10^(-11) N
Explanation:
F = Gm²/r²
F = 6.67×10^(-11) × 60² / 100²
= 2.4×10^(-11) N
Momentum will be conserved in one dimension in the explosion.
<span>
Given that the fragment a acquires three
times the kinetic energy of the fragment b.
<span>
P</span><span><span>initial </span><span>= p</span></span>final ⇒ 0 =mₐv⁰ₐ+mьv⁰ь= 0 ⇒ v⁰ь = -mₐv⁰ₐ/mь
KE= 3KEь
⇒1/2 mₐv⁰ₐ² = 3 (1/2mьv⁰ь²)
</span><span>
⇒1/2 mₐv⁰ₐ² = 3/2 mь(-mₐv⁰ₐ/mь)²
⇒1/2 mₐv⁰ₐ² = 3/2 mь(mₐ²v⁰ₐ²/mь²)
</span>
⇒1/2 x 2/3 = mₐ/mь= 1/3
<span>
<span>
Thus the ratio
of the masses of the fragments is 1:3.
</span></span>
In order to determine the acceleration of the block, use the following formula:
Moreover, remind that for an object attached to a spring the magnitude of the force acting over a mass is given by:
Then, you have:
by solving for a, you obtain:
In this case, you have:
k: spring constant = 100N/m
m: mass of the block = 200g = 0.2kg
x: distance related to the equilibrium position = 14cm - 12cm = 2cm = 0.02m
Replace the previous values of the parameters into the expression for a:
Hence, the acceleration of the block is 10 m/s^2
Moles x Mol mass = mass.
<span>Having looked it up, the mol.mass of U-238 is 238.03g/mol. </span>
<span>7.50 moles x 238.03g/mol. = 1,785.23g/mol</span>
We can answer this problem using Ampere’s Law:
<span>Bh = μoNI </span>
Where:
B = Magnetic Field
h = coil length
<span>μo = permeability =4π*10^-7 T·m/A </span>
N = number of turns
I = current
It is given that B=0.0015T, I=1.0A, h=10 cm =
0.1m<span>
Use Ampere's law to find # turns:
Which can be rewritten as:
<span>N = Bh/μoI </span>
N = (0.0015)(0.1)/(4π*10^-7)(1.0)
N = 119.4
</span>
<span>Answer:
119.4 turns</span>
