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andrezito [222]
3 years ago
11

How do open-market operations change the money supply?

Physics
1 answer:
Greeley [361]3 years ago
6 0
If they want to increase the money supply<span> in the economy it </span>will<span> buy securities. Conversely, if the they want to </span>decrease the money supply<span>, it </span>will<span> sell securities.</span>
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Which applications, either for diagnostic purposes or for therapeutic purposes, do not involve ionizing radiation? Check all tha
neonofarm [45]

These applications DO NOT INVOLVE harmful ionizing energy:

- MRI

- ultrasound

- laser surgery

5 0
3 years ago
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Which of the following is the method by which air is cooled in the food storage component of a refrigerator?
dem82 [27]

Answer: Convection :)

3 0
3 years ago
The unit of current, the ampere, is defined in terms of the force between currents. Two 1.0-meter-long sections of very long wir
Paha777 [63]

Answer:

1.6 x 10^{-7} N

Explanation:

If the force between two actual wires has this value, the current is defined to be exactly 1 A.

The force between two parallel wires carrying current can be defined as,

F=  μI_{1} I_{2} L/ 2πd

where,

current I_{1} = 1Amp

current I_{2} = 2amp

Length 'L'= 1m

distance 'd'= 2.5m

permeability of free space 'μ'= 4πx10^{-7} N/m

Putting the above values in the equation,

F=( 4πx10^{-7} x 1 x 2 x 1 )/ 2πx2.5

F= 1.6 x 10^{-7} N

8 0
3 years ago
The equation for photosynthesis is 6H2O (water) + 6CO2 (carbon dioxide) + Light Energy → C6H12O6 (glucose) + 6O2 (oxygen). When
aleksklad [387]

Answer:

b

Explanation:

bc

8 0
3 years ago
Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The
IRISSAK [1]

To develop this problem we will apply the concepts related to the Electromagnetic Force. The magnetic force can be defined as the product between the free space constant, the current (of each cable) and the length of these, on the perimeter of the cross section, in this case circular. Mathematically it can be expressed as,

F= \frac{\mu_0}{2\pi} \frac{I^2L}{d}

Here,

\mu_0 = Permeability free space

I = Current

L = Length

d= Distance between them

Our values are,

L = 0.67m

m = 0.082kg

d = 7.4*10^{-3}m

I = \text{Current through each of the wires}

Rearranging the previous equation to find the current,

\frac{mg}{L} = 2*10^{-7} (\frac{I^2}{d})

I = \sqrt{\frac{mgd}{(2*10^{-7})L}}

I = \sqrt{\frac{(0.082)(9.8)(7.4*10^{-3})}{(2*10^{-7})(0.67)}}

I = \sqrt{44377.9}

I = 210.66A

Therefore the current in the rods is 210.6A

8 0
3 years ago
Read 2 more answers
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