A rectangle is drawn so that the width is 3 feet shorter than the length. the area of the rectangle is 40 square feet. find the
1 answer:
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Answer:
Attachment 1 : 5x + 6y = 5, Attachment 2 : 4cotθcscθ
Step-by-step explanation:
Remember that we have three key points in solving these types of problems,
• x = r cos(θ)
• y = r sin(θ)
• x² + y² = r²
a ) For this first problem we need not apply the third equation.
( Multiply either side by 5 cos(θ) + 6 sin(θ) )
r ( 5 cos(θ) + 6 sin(θ) ) = 5,
( Distribute r )
5r cos(θ) + 6r sin(θ) = 5
( Substitute )
5x + 6y = 5 - the correct solution is option c
b ) We know that y² = 4x ⇒
r²sin²(θ) = 4r cos(θ),
r = 4cos(θ) / sin²(θ) = 4 cot(θ) csc(θ) = 4cotθcscθ - again the correct solution is option c
Answer:
XY = 16 ft
Step-by-step explanation:
The mid segment DE is half the sum of the parallel bases, that is
= 20 ( multiply both sides by 2 to clear the fraction )
XY + WZ = 40
XY + XY = 40 ( multiply through by 2 to clear the fraction )
2XY + 3XY = 80
5XY = 80 ( divide both sides by 5 )
XY = 16