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postnew [5]
3 years ago
10

A rectangle is drawn so that the width is 3 feet shorter than the length. the area of the rectangle is 40 square feet. find the

length of the rectangle.
Mathematics
1 answer:
Tpy6a [65]3 years ago
3 0
Draw a rectangle and label the right side as L-3 and the bottom side as L.

Area is L x W...in this case L(L-3) = 40.....we get

L^2 - 3L = 40  (subtract 40 from each side we get...)
L^2 - 3L - 40 = 0  (factor this out to get the L and W)

8 and 5
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In quadrilateral ABCD,AB produced is perpendicular to DC produced.If A=44° and C=148°,calculate D and B.
7nadin3 [17]
Let AB extended intersect DC extended at point E 
<span>We now have right triangle BEC with E = 90 degrees </span>

<span>For triangle BEC: </span>
<span>Exterior angle at E = 90 </span>
<span>Exterior angle at C = 148 (given) </span>
<span>Exterior angle of all polygons add up to 360 degrees </span>
<span>Exterior angle at B = 360−148−90 = 122 </span>

<span>So in quadrilateral ABCD </span>
<span>B = 122 </span>
<span>D = 360−44−148−122 = 46</span>
5 0
3 years ago
In the last ten games, Jamal made 7/9 of his free throws and brian made 5/8 of bis free throws. Which player has the better reco
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4 0
3 years ago
Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes
azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

  • The centre of the ellipse is at the origin and the X axis is the major axis

  • It passes through the points (-3, 1) and (2, -2)

<h2>To Find:</h2>

  • The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1

Given that the ellipse passes through the point (-3, 1)

Hence,

\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1

Cross multiplying we get,

  • 9b² + a² = 1 ²× a²b²
  • a²b² = 9b² + a²

Multiply by 4 on both sides,

  • 4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1

Cross multiply,

  • 4b² + 4a² = 1 × a²b²
  • a²b² = 4b² + 4a²-------(2)

Subtracting equations 2 and 1,

  • 3a²b² = 32b²
  • 3a² = 32
  • a² = 32/3----(3)

Substituting in 2,

  • 32/3 × b² = 4b² + 4 × 32/3
  • 32/3 b² = 4b² + 128/3
  • 32/3 b² = (12b² + 128)/3
  • 32b² = 12b² + 128
  • 20b² = 128
  • b² = 128/20 = 32/5

Substituting the values in the equation for ellipse,

\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1

\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>
8 0
3 years ago
Jeff bought a new jacket that had a regular price of $75.99. His mom gave him a 30% off coupon. What is the price he pays includ
solmaris [256]
  • Answer:98.99

  • Step-by-step explanation:
  • So we are gonna do 75.99+30-7=98.99 so basically he won't have enough money. Hope dat helps

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3 years ago
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Helen [10]
6 and 8 I believe is the answer
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