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nekit [7.7K]
3 years ago
5

Help me please I’ve been stuck on this forever now ☹️

Physics
2 answers:
valina [46]3 years ago
7 0
C, velocity I believe this is the answer to your question
castortr0y [4]3 years ago
5 0
Hey !  If you've already been stuck on it forever, then
a few more days won't make that much difference.

No, I'm just kidding.  I wouldn't do that to you.

I'm sure this is all stuff that you've heard before.
Here it is again, all in one place:
____________________________________

-- LOCATION . . . . . a point.
If you move from one point to another point, then you travel a
 
-- DISTANCE . . . . . the path you followed between two points.
If you're moving right now, then how fast you're moving is your

-- SPEED . . . . . the RATE of how fast your distance is changing.
If we also know what DIRECTION you're moving, then we know your

-- VELOCITY . . . . . your speed AND direction.
If your speed is changing OR your direction is changing, then you have 

-- ACCELERATION . . . . . the RATE of how fast your speed or your direction is changing.
____________________________________

Go through it again, in the other direction:

Acceleration . . . the rate of how fast your velocity is changing.

Velocity . . . your speed AND your direction.

Speed . . . the rate of how fast your distance is changing.

Distance . . . the length of the path you walk from one place to another.
___________________________________

For the question on the screen:

Instantaneous acceleration describes how fast a velocity is changing
at a specific instant.
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The combined focal length of two thin lens is 24 cm and the focal length of one converging lens is 8
qwelly [4]

Answer: f = -12 cm

Explanation: <u>Combined</u> <u>lenses</u> is an array of  simple lenses with a common axis. The combination is useful for correction of optical aberrations which cannot be corrected by simple lenses.

When two lenses are in contact and are thin, focal lengths are related as:

\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}}

If there is a distance between the lenses, the focal length will be:

\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}} -\frac{d}{f_{1}f_{2}}

Since the lenses in the question above are thin and in contact, the focal length of one of them will be:

\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}}

\frac{1}{f_{2}} =\frac{1}{f_{1}} -\frac{1}{F}

\frac{1}{f_{2}} =\frac{1}{8} -\frac{1}{24}

\frac{1}{f_{2}} =\frac{-2}{24}

f_{2}= -12

The focal length of the other lens is -12 cm, with the negative sign meaning it's a converging lens.

7 0
3 years ago
A rock of mass m is twirled on a string in a horizontal plane. The work done by the tension in the string on the rock is:
Varvara68 [4.7K]

Answer: c) 0

Explanation:

Work tension is zero because in any infinitesimal time interval, the tension force is directly perpendicular to the displacement.

7 0
3 years ago
When the top right-hand capacitor is filled with a material of dielectric constant κ, the charge on this capacitor is increases
Olin [163]

Answer: k = 2.07692

Explanation: Please find the attached files for the solution

6 0
3 years ago
Read 2 more answers
HELPPP WILL MARK BRAINLIST What type of image is formed by a lens if m= 2.7?
Gelneren [198K]

Answer:

the answer is C

Explanation:

So, the formed image will be real and inverted.

6 0
3 years ago
A tennis ball is dropped from a roof. If it takes 38.9 seconds to reach the ground, how fast is the ball moving just before it h
Ilya [14]

Answer:

The velocity of the ball before it hits the ground is 381.2 m/s

Explanation:

Given;

time taken to reach the ground, t = 38.9 s

The height of fall is given by;

h = ¹/₂gt²

h = ¹/₂(9.8)(38.9)²

h = 7414.73 m

The velocity of the ball before it hits the ground is given as;

v² = u² + 2gh

where;

u is the initial velocity of the on the root = 0

v is the final velocity of the ball before it hits the ground

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 7414.73 )

v = 381.2 m/s

Therefore, the velocity of the ball before it hits the ground is 381.2 m/s

5 0
3 years ago
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