Help...!!!!!!!! Please....!!!!

Mathematics

1 answer:

IRINA_888 [86]3 years ago

5 0

Answer:

5x^2 + -3

Step-by-step explanation:

For this problem, we will simply simplify the expression by combining like terms.

(-3x^3 - 7x^5 - 3) + (5x^2 + 3x^3 + 7x^5)

= 7x^5 + -7x^5 + 3x^3 + -3x^3 + 5x^2 + -3

= 0 + 0 + 5x^2 + -3

= 5x^2 + -3

Thus, the simplified expression is 5x^2 + -3.

Cheers.

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John and Tim are looking at the equation the square root of the quantity of 3 times x minus 4 equals square root of x . John say

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The equation is
3x - 4 = sqrt(x)
where 'sqrt' is shorthand for 'square root'

Let's solve the equation. To do so, we square both sides. Then we get everything to one side
3x - 4 = sqrt(x)
(3x - 4)^2 = (sqrt(x))^2
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9x^2 - 24x + 16-x = x-x
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Now use the quadratic formula. See the attached image for those steps.

After using the quadratic formula the two possible solutions are x = 1 or x = 16/9

We need to check each possible solution to see if it is extraneous or not.

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Checking x = 1

3x - 4 = sqrt(x)
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3 - 4 = 1
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The final equation is false, so x = 1 is not a true solution

x = 1 is extraneous.

So far, John is correct; however, we need to see the nature of the possible solution x = 16/9

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Checking x = 16/9

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This solution is considered non-extraneous. So Tim is also correct
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They are both correct because there are two possible solutions. One of which is extraneous (x = 1) and the other is non-extraneous (the fraction x = 16/9)

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