The lowest value of the henry's law for methane gas (ch4) will be obtained with __________ as the solvent and a temperature of _
1 answer:
The lowest value of the henry's law for methane gas (CH₄) will be obtained with H₂O as the solvent and a temperature of 349 K.
The lowest value of the henry's law for methane gas (CH₄) will be obtained with H₂O as the solvent and a temperature of 349 K.
Henry's law: This law states that at a constant temperature, the amount of a gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas that in equilibrium with that liquid.
Mathematically it can be written as:
So, for the methane gas , lowest value of the henry's law obtained at 349 K and with H₂O as the solvent.
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Question is incomplete, complete question is as follows :
Complete Question : .Sulfonation of benzene has the following mechanism:
(1) 2 H2SO4 ⇌ H3O+ + HSO4− + SO3
[fast]
(2) SO3 + C6H6 → H(C6H5+)SO3−
[slow]
(3) H(C6H5+)SO3− + HSO4− → C6H5SO3− + H2SO4
[fast]
(4) C6H5SO3− + H3O+ → C6H5SO3H + H2O
[fast]
write the overall rate law for the initial rate of the reaction as a fraction.
Rate=k(________/_________)
Answer:
The overall rate law for the initial reaction is =
Explanation :
Frist of all, all the common terms are cancelled out and written the overall reaction.
As we know that the rate depednant step is the slowest step of the reaction, rate law is :
rate =
But the problem is that SO3 cannot be written in the overall rate law because it is an intermediate.
Rate law for synthesis of S03 is as follows :
rate =
Hence when we substitute equation 2 in equation one,
Rate comes out to be =