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viktelen [127]
3 years ago
8

Which of the following in the definition of control?

Chemistry
1 answer:
Advocard [28]3 years ago
5 0
D The Part That Stays The Same
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What type of evidence does the author use to support his argument that students should be required to complete service hours in
SpyIntel [72]
Answer:C



Explanation:
C. The author presents rational and logical reasons to support his argument
4 0
3 years ago
The molecular structure of water has an asymmetrical arrangement of hydrogen atoms causing.
Sergio [31]

Answer:

the asymmetrical arrangement of hydrogen atoms in a molecule of water causes the molecule to be polar, with the hydrogen atoms having a slightly positive charge, and the oxygen atom having a slightly negative charge.

3 0
2 years ago
The concentration of dye in Solution A is 25.527 M. You have 13 mL of water at your disposal to make the dilutions. The solution
Lady bird [3.3K]

Answer:

 38825.472 M

Explanation:

Using

C1V1=C2V2

To make solution B,

C1 = 25.527 M, V1 = 13 mL

C2 = 25.527 x 8 = 204.216 M

V2 = 13 X 12 = 156 mL

To make solution C'

C1 = 8 X 202.216 M = 1617.728

V1 = 8 X 156mL = 1248 mL

V2 = 4 X 13 = 52 mL

C2 = C1V1 / V2

    =1617.728 X 1248 / 52

 =38825.472 M

7 0
3 years ago
Consider this question: What is the molarity of KMnO4 in a solution of 0.0908 g of KMnO4 in 0.500 L of solution?
natita [175]

Answer:

0.0011 M.

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity

V = volume of solution in liter ,

n = moles of solute ,

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the question ,

w = given mass of KMnO₄ = 0.0908 g

and ,

V = 0.500 L

Since ,

we know ,

m = Molecular mass of   KMnO₄ =  158 g/mol

using , the above formula to calculate the moles ,

n = w / m = 0.0908 g / 158 g/mol = 0.00057 mol

now , calculating the molarity as ,

M = n / V =  0.00057 mol / 0.500 L = 0.0011 M.

6 0
3 years ago
A gas that has a volume of 28 liters, a temperature of 45 °C, and an unknown pressure has its volume increased
allochka39001 [22]

Answer:

2.5 atm

Explanation:

V1 = 28L

T1 = 45°C = (45 + 273.15)K = 318.15K

V2 = 34L

T2 = 35°C = (35 + 273.15)K = 308.15k

P2 = 2.0atm

P1 = ?

From general gas equation,

(P1 × V1) / T1 = (P2 × V2) / T2

P2 × V2 × T1 = P1 × V1 × T2

P1 = (P2 × V2 × T1) / (V1 × T2)

P1 = (2.0 × 34 × 318.15) / (28 × 308.15)

P1 = 21634.5 / 8628.2

P1 = 2.5 atm

The initial pressure of the gas is 2.5atm

5 0
3 years ago
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