Answer:
<span>Formula for sodium hydroxide is represented by <u>NaOH</u>.
Explanation:
The reaction of Sodium oxide with water is as follow,
Na</span>₂O + H₂O → 2 NaOH
<span>
Na</span>₂O is considered as a strong basic oxide as it contains O²⁻ which has high tendency to bind with hydrogen atoms. This reaction is an exothermic reaction and is conducted in cold water to produce NaOH.<span>
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What is the oxidation number of iodine in kio4? -7?
Answer:
18.76 g of copper II nitrate
Explanation:
Now recall that we must use the formula;
n= CV
Where;
n= number of moles of copper II nitrate solid
C= concentration of copper II nitrate solution
V= volume of copper II nitrate solution
Note that;
n= m/M
Where;
m= mass of solid copper II nitrate
M= molar mass of copper II nitrate
Thus;
m/M= CV
C= 0.05 M
V= 2.00 L
M= 187.56 g/mol
m= the unknown
Substituting values;
m/ 187.56 g/mol = 0.05 M × 2.00 L
m= 0.05 M × 2.00 L × 187.56 g/mol
m= 18.76 g of copper II nitrate
Therefore, 18.76 g of copper II nitrate is required to make 0.05 M solution of copper II nitrate in 2.00 L volume.
Answer:
Greater. Inversely proportional
Explanation:
