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kvasek [131]
3 years ago
12

PLEASE ANSWER ASAP BEFORE MY TEACHER AND MY MOM KILLES ME PLEASE ASAP

Physics
1 answer:
Anastaziya [24]3 years ago
6 0

Answer:

As you know, the denser objects have more weight per unit of volume, this will mean that the force that pulls down these objects is a bit larger.

This will mean that the denser objects will always go to the bottom.

This clearly implies that the red liquid, the one with one of the smaller densities, can not be at the bottom.

There are some cases where a liquid with a small density may become a lot denser as the temperature or pressure changes, and in a case like that, we could see the red liquid at the bottom, but for this case, there is no mention of changes in the temperature nor in the pressure, so this can be discarded.

The only thing that makes sense is that the red part at the bottom is the base of the tube, and has nothing to do with the red liquid.

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Two capacitors give an equivalent capacitance of 9.42 pF when connected in parallel and an equivalent capacitance of 1.68 pF whe
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Answer:

C_1=7.23pF\ and\ C_2=2.19pF

Explanation:

Let the two capacitance are C_1\ and\ C_2

It is given that when capacitors are connected in parallel their equvilaent capacitance is 9.42 pF

So C_1+ C_2=9.2--------EQN 1

And when they are connected in series their equivalent capacitance is 1.68 pF

So \frac{1}{C_1}+\frac{1}{C_2}=\frac{1}{1.68}

\frac{C_1+C_2}{C_1C_2}=\frac{1}{1.68}

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C_1-C_2=\sqrt{(C_1+C_2)^2-4C_1C_2}=\sqrt{9.42^2-4\times 15.8256}=5.0432pF-----EQN

On solving eqn 1 and eqn 2

C_1=7.23pF\ and\ C_2=2.19pF

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