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lisov135 [29]
3 years ago
15

18 Powdered sulfur is yellow, and powdered iron is gray. When powdered sulfur and powdered iron are mixed at 20°C, the powdered

iron
(1) becomes yellow (3) remains ionic
(2) becomes a liquid (4) remains magnetic
Chemistry
1 answer:
MAXImum [283]3 years ago
7 0
Powered sulfur is yellow, and powdered iron is gray. When powered sulfur are mixed at 20 degrees C, the powered iron remains magnetic.
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Just need help with these two questions
kvasek [131]
B/A hope it help thanks
8 0
3 years ago
In a balanced equation, the same number of each kind of atom is shown on each side of the equation. calculate the number of iron
Juliette [100K]
There is a missing portion of this question which shows the reaction that needs balancing:

"In a balanced equation, the same number of each kind of atom is shown on each side of the equation. Calculate the number of iron (Fe), oxygen (O), and carbon atoms (C).

Fe2O3+ 3CO --> 2Fe + 3CO<span>2

</span><span>Based on these values, is the equation balanced?</span><span>"
</span>
To check if this equation is balanced we simply compare the number of each element on each side of the equation.

On the reactant side of the equation we have:

2 Fe atoms
6 O atoms
3 C atoms

On the product side of the equation we have:

2 Fe atoms
6 O atoms
3 C atoms

Therefore, both side of the reaction have the correct and equal number of each atom, so the equation is balanced.
7 0
3 years ago
Read 2 more answers
A coffee-cup calorimeter initially contains 125 g water at 24.28C. Potassium bromide (10.5 g), also at 24.28C, is added to the w
iren2701 [21]

Answer:

The solution is given below

Explanation:

Heat, q= mc∆T

q= 125g x 4.18 J/g∙°C x (21.18x- 24.28) °C

q=  -1619.75J

NEGATIVE SIGN INDICATES THAT HEAT IS ABSORBED.

Enthalpy Change, ∆H = 1619.75 7/ 10.5 g

                                     = 154.26 J/g

No. of moles of KBr = Mass of KBr/ Molecular Weight of KBr

                                =10.5g/119gmol-1

                                =0.088 mol

∆H= 1619.75 J/ 0.088 mol

      = 18.41 kJ/mol  

6 0
4 years ago
Given that the nucleophilic substitution reaction used 5.0 mL of t-pentyl alcohol and 12.0 mL of conc. hydrochloric acid to prod
Vladimir [108]

Answer:

4.90 g

Explanation:

Given that:

volume of t-pentyl alcohol = 5 mL

the standard density of t-pentyl alcohol = 0.805 g/mL

Recall that:

density = mass(in wt) /volume

mass = density × volume

mass = 0.805 g/mL × 5 mL

mass = 4.03 g

Volume of HCl used = 12 mL

The reaction for this equation is shown in the image attached below.

From the reaction,

88.15 g of t-pentyl alcohol reacts with concentrated HCl to yield 106.59 g pf t-pentyl chloride.

4.03 g of t-pentyl alcohol forms,

= \dfrac{106.59 \ g \times 4.03 \ g}{88.15 \ g} of t-pentyl chloride.

Therefore,

Theoretical yield of t-pentyl chloride = 4.90 g

8 0
3 years ago
Classify each of the following substances as an acid or a base according to the Arrenius Definition:
Vladimir79 [104]

Answer:

i dont know lol

Explanation:

7 0
3 years ago
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