Answer:
100°C
Explanation:
The following were obtained from the question:
Initial temperature (T1) = 298 K
Initial pressure (P1) = 32.5 Psi
Final pressure (P2) = 40.68 Psi
Final temperature (T2) =..?
The final temperature can be obtained as follow:
P1/T1 = P2/T2
32.5/298 = 40.68/T2
Cross multiply to express in linear form
32.5 x T2 = 298 x 40.68
Divide both side by 32.5
T2 = (298 x 40.68) /32.5
T2 = 373K
Next, we shall convert 373K to celsius.
This is illustrated below:
T(°C) = T(K) – 273
T(K) = 373
T(°C) = 373 – 273
T(°C) = 100°C
Therefore, the temperature of the air inside the tire at 40.68 Psi is 100°C
Answer:
Check the explanation
Explanation:
1.
Kindly check the first image for the Synthesis reaction
2.
Kindly check the second image for the Single replacement reaction
3.
Kindly check the second image for the Double displacement reaction
Activation energy Enthalpy change
Synthesis reaction 45 KJ +35 KJ
Single replacement reaction 20KJ -35 KJ
Double replacement 65 KJ +50KJ
Answer:
option a
Explanation:
The group number of an element is equal to the number of electrons the outermost shell (or highest energy level) contains
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