Question

What would be the temperature change 3.0 g of water absorbed 15 J of heat

Answer 1

Answer:

1.2 °C  

Step-by-step explanation:

The formula relating the heat (q) absorbed by an object, the mass (m), and the temperature change (ΔT) is

  q = mCΔT     Divide both sides by mC  

ΔT = q/(mC)

Data:

q  = 15 J

m = 3.0 g

C  = 4.184 J·°C⁻¹g⁻¹

Calculation:

ΔT = 15/(3.0 × 4.184)

ΔT = 15/12.6

ΔT = 1.2 °C