Answer:
6.5 m above the floor and 5 m above Christine's hand when it reaches the maximum height.
Explanation:
Let g = 10 m/s2 be the gravitational deceleration that affects the ball vertical motion so it comes to the maximum height at 0 speed. We can use the following equation of motion to find out the distance traveled by the ball from where it's thrown:
where v = 0 m/s is the final velocity of the ball when it reaches maximum level, 
= 10m/s is the initial velocity of the ball when it starts, g = -10 m/s2 is the deceleration, and 
is the distance traveled, which we care looking for:
So the ball is 5 m above Christine' hands when it reaches maximum height, and since the hand is 1.5 m above the floor, the ball is 5 + 1.5 = 6.5 m above the floor when it reaches maximum height.
At New Moon the percent illuminated is 0; at First and Last Quarters it is 50%; and at Full Moon it is 100%<span>. During the crescent phases the percent illuminated is between 0 and </span>50%<span> and during gibbous phases it is between </span>50%<span> and </span>100%<span>.
so it depends on the phase
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Answer:
The answer to your question is T2 = 580.5 °K
Explanation:
Data
Temperature 1 = T1 = 273°K
Pressure 1 = P1 = 388 kPa
Pressure 2 = P2 = 825 kPa
Temperature 2 = ?
Process
1.- Use the Gay-Lussac law
P1/T1 = P2/T2
-Solve for T2
T2 = P2T1/P1
-Substitution
T2 = (825)(273) / 388
-Simplification
T2 = 225225 / 388
-Result
T2 = 580.5 °K
Answer:
Stir/agitate and heat the tea
