Answer:
transmit energy
Explanation:
hope this helps u stay safe
Answer:
a) see attached, a = g sin θ
b)
c) v = √(2gL (1-cos θ))
Explanation:
In the attached we can see the forces on the sphere, which are the attention of the bar that is perpendicular to the movement and the weight of the sphere that is vertical at all times. To solve this problem, a reference system is created with one axis parallel to the bar and the other perpendicular to the rod, the weight of decomposing in this reference system and the linear acceleration is given by
Wₓ = m a
W sin θ = m a
a = g sin θ
b) The diagram is the same, the only thing that changes is the angle that is less
θ' = 9/2 θ
c) At this point the weight and the force of the bar are in the same line of action, so that at linear acceleration it is zero, even when the pendulum has velocity v, so it follows its path.
The easiest way to find linear speed is to use conservation of energy
Highest point
Em₀ = mg h = mg L (1-cos tea)
Lowest point
Emf = K = ½ m v²
Em₀ = Emf
g L (1-cos θ) = v² / 2
v = √(2gL (1-cos θ))
The forces acting on your mom while cooking is Air resistance and the force of friction
<u>Explanation:</u>
<u>1. Air resistance:</u>
- In simple words, Air resistance can be stated as the type of friction between the air and the other materials.
- In this scenario, there will be an air resistance and the air hits the mom while cooking via the doors or windows
<u>2. The force of friction:</u>
- In simple words, friction can be stated as, the resistance that one surface or object encounters when moving over another.
- While cooking the food mom would experience the friction since friction is the transfer of heat, and cooking is the process of receiving that heat.
As per Bernuolli's Theorem total energy per unit mass is given as
now from above equation
now by above equation
Part B)
Now energy per unit weight
The second and third laws of thermodynamics states that absolute zero cannot be reached. The correct option among all the options that are given in the question is the third option or option "C". Both the laws actually deal with the relations that exist between heat and other forms of energy. I hope the answer helps you.