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Ad libitum [116K]
3 years ago
11

How many atoms are in 35.1 g of sodium chloride (NaCl) ?

Chemistry
1 answer:
hoa [83]3 years ago
8 0

Answer:

I believe that there are 70.2

Explanation:

There are 2 atoms in sodium chloride so I x 35.1 by 2 and got 70.2

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How many liters of Cl2 gas will you have if you are using 63 g of Na?
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Answer:

You will have 19.9L of Cl2

Explanation:

We can solve this question using:

PV = nRT; V = nRT/P

<em>Where V is the volume of the gas</em>

<em>n the moles of Cl2</em>

<em>R is gas constant = 0.082atmL/molK</em>

<em>T is 273.15K assuming STP conditions</em>

<em>P is 1atm at STP</em>

The moles of 63g of Cl2 gas are -molar mass: 70.906g/mol:

63g * (1mol / 70.906g) = 0.8885 moles

Replacing:

V = 0.8885mol*0.082atmL/molK*273.15K/1atm

V = You will have 19.9L of Cl2

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Answer:

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Explanation:

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