Gases can be compressed, because they just take up the space surrounding them. The attractive forces between the particles in a gas are very weak, so the particles are free to move in random direction. They just move along until they collide, either with the walls of the container or with each other. Moreover, gases can be compressed because the particles are far apart and they have space to move into.
Answer:
![x_2=1.60m](https://tex.z-dn.net/?f=x_2%3D1.60m)
Explanation:
From the Question We are told that
Initial Force ![F_1=5800N](https://tex.z-dn.net/?f=F_1%3D5800N)
Final Force ![F_2=6500N](https://tex.z-dn.net/?f=F_2%3D6500N)
Distance between the front and rear wheels \triangle x=3.20 m
Since
![\triangle x=3.20 m](https://tex.z-dn.net/?f=%5Ctriangle%20x%3D3.20%20m)
Therefore
![x_1+x_2=3.20](https://tex.z-dn.net/?f=x_1%2Bx_2%3D3.20)
![x_1=3.20-x_2](https://tex.z-dn.net/?f=x_1%3D3.20-x_2)
Generally the equation for The center of mass is at x_2 is mathematically
given by
![x_2 =\frac{(F_1x_1+F_2x_2)}{(F_1+F_2)}](https://tex.z-dn.net/?f=x_2%20%3D%5Cfrac%7B%28F_1x_1%2BF_2x_2%29%7D%7B%28F_1%2BF_2%29%7D)
![x_2=3.20F_1-\frac{x_2F_1+F_2x_2}{(F_1+F_2)}](https://tex.z-dn.net/?f=x_2%3D3.20F_1-%5Cfrac%7Bx_2F_1%2BF_2x_2%7D%7B%28F_1%2BF_2%29%7D)
![2*F_1*x_2 =3.20F_1](https://tex.z-dn.net/?f=2%2AF_1%2Ax_2%20%3D3.20F_1)
![x_2=1.60m](https://tex.z-dn.net/?f=x_2%3D1.60m)
Answer:
Average speed is 60 km/hour
Explanation:
When we need to calculate average speed, we use this equation:
![V = \frac{x_{f} - x_{o}}{t_{f} - t_{o}}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7Bx_%7Bf%7D%20-%20x_%7Bo%7D%7D%7Bt_%7Bf%7D%20-%20t_%7Bo%7D%7D)
Where:
position at the beginning
at the end
![t_{o} = 0 hours](https://tex.z-dn.net/?f=t_%7Bo%7D%20%3D%200%20hours)
![t_{f} = 4 hours](https://tex.z-dn.net/?f=t_%7Bf%7D%20%3D%204%20hours)
Then: ![V = \frac{240 km - 0 km}{4 hours - 0 hours}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B240%20km%20-%200%20km%7D%7B4%20hours%20-%200%20hours%7D)
![V = \frac{240 km}{4 hours}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B240%20km%7D%7B4%20hours%7D)
Finally V = 60 km/hour
Answer:
![v = 3869 m/s](https://tex.z-dn.net/?f=v%20%3D%203869%20m%2Fs)
Explanation:
As we know that the orbital speed of the satellite is given as
![v = \sqrt{\frac{GM}{r}}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B%5Cfrac%7BGM%7D%7Br%7D%7D)
also we know that
time period of the revolution is given as
![T = \frac{2\pi r}{v}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B2%5Cpi%20r%7D%7Bv%7D)
now from above equation we know that
![T = \frac{2\pi (\frac{GM}{v^2})}{v}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B2%5Cpi%20%28%5Cfrac%7BGM%7D%7Bv%5E2%7D%29%7D%7Bv%7D)
![T = \frac{2\pi GM}{v^3}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B2%5Cpi%20GM%7D%7Bv%5E3%7D)
so we will have
![v = (\frac{2\pi GM}{T})^{1/3}](https://tex.z-dn.net/?f=v%20%3D%20%28%5Cfrac%7B2%5Cpi%20GM%7D%7BT%7D%29%5E%7B1%2F3%7D)
now plug in all data in this equation
![v = (\frac{2\pi (6.67 \times 10^{-11})(5.97 \times 10^{24})}{12 \times 3600})^{1/3}](https://tex.z-dn.net/?f=v%20%3D%20%28%5Cfrac%7B2%5Cpi%20%286.67%20%5Ctimes%2010%5E%7B-11%7D%29%285.97%20%5Ctimes%2010%5E%7B24%7D%29%7D%7B12%20%5Ctimes%203600%7D%29%5E%7B1%2F3%7D)
![v = 3869 m/s](https://tex.z-dn.net/?f=v%20%3D%203869%20m%2Fs)
60 N because 98N=mg (here g= 9.8 on earth) thus mass can be calculated which is 98/9.8 = 10kg
Now,new weight with g = 6m/s^2
=m×g' (here g' is new acceleration of the new planet)
= 10×6=60N