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kogti [31]
3 years ago
13

A fly travels along the x-axis. His starting point is x = 16 m and his ending point 15x = - 25 m. His flight lasts 4.0 seconds H

ow far has he flown, what is his displacement , what is his speed and what is his velocity?
Physics
1 answer:
gogolik [260]3 years ago
5 0

Explanation:

Starting position at x  = 16m

Ending position at x  = -25m

Time of flight  = 4s

Unknown:

Distance flown  = ?

Displacement  = ?

Speed  = ?

Velocity  = ?

Solution:

To find the distance flown, we should understand that the body is moving on the x - plane;  

  So distance  = 16 + 25  = 41m

Displacement is 41m to the left or -x axis

Speed is the distance divided by the time taken;

      Speed  = \frac{distance}{time}   = \frac{41}{4}   = 10.25m/s

Velocity is 10.25m/s along -x axis

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If you put 300 J of heat into an engine with an efficiency of 0.35, how much work can be done? 3. How much energy must be put into an engine with an efficiency of 0.6 if 270 J of work are required? 4. An engine with an efficiency of 0.425 uses 1200 J of energy. Find the amount of energy wasted by the engine. 5. Calculate the efficiency of an engine operating between temperatures of 258 K and 600 K 6. An engine runs with its exhaust (cold) reservoir at a temperature of 200 K. To what temperature should the input (hot) temperature be set if an efficiency of 0.8 is desired? 7. Complete the following table of temperatures. Fahrenheit Celsius Kelvin 213 15 98.6 75 408

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3 years ago
A uniform solid disk and a uniform hoop are placed side by side at the top of an incline of height h. If they are released from
svlad2 [7]

Answer:

) the uniform disk has a lower moment of inertia and arrives first.

Explanation:

(a) the uniform disk has a lower moment of inertia and arrives first.

(b) Let's say the disk has mass m and radius r, and

the hoop has mass M and radius R.

disk: initial E = PE = mgh

I = ½mr², so KE = ½mv² + ½Iω² = ½mv² + ½(½mr²)(v/r)² = (3/4)mv² = mgh

m cancels, leaving v² = 4gh / 3

hoop: initial E = Mgh

I = MR², so KE = ½MV² + ½(MR²)(V/R)² = MV² = Mgh

M cancels, leaving V² = gh

Vdisk = √(4gh/3) > Vhoop = √(gh)

3 0
3 years ago
A 22 kg solid door is 220 cm tall, 91 cm wide. a) What is the door's moment of inertia for rotation about a vertical axis inside
iris [78.8K]

Answer

given,

mass of the solid door = 22 Kg

dimension of door = 220 cm x 91 cm

moment of inertia about the hinge

   I = \dfrac{1}{3}Mr^2

r is the distance from the one edge which is equal to 91 cm or 0.91 m

   I = \dfrac{1}{3}\times 22 \times 0.91^2

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Moment of inertia about center for rectangular gate is equal to

   I_{CM} = \dfrac{1}{12}Mr^2

moment of inertia for rotation about a vertical axis inside the door, 15 cm from one edge

   I = I_{CM} + MR^2

   I = I_{CM} + M(\dfrac{91}{2}- 15)^2

   I = \dfrac{1}{12}Mr^2+ M(0.0930)

  I = \dfrac{1}{12}\times 22 \times 0.91^2+ 22 \times (0.093)

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3 0
4 years ago
(a) During an ice skating performance, an initially motionless 80.0-kg clown throws a fake barbell away. The clown’s ice skates
nlexa [21]

Answer:

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c)Newton's Third Law of Motion; explained more below

Explanation:

I'm always weary of Physics problems so I apologize ahead of time if this comes out wrong.

a) We know that in a system, the initial energy input must equal the final energy that is output. I'm going to assume part b) is regarding the energy of the clown's movement; meaning the clown is our "system". And since the system disregards friction we have a system where the initial side has the energy of the clown and the barbell, while the final side just has the final energy of the clown. This gives us:

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The clown is initially standing still on the ice, so the initial clown velocity is 0; which wipes out that part of the equation. Plugging in our knowns, we end up with:

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b) Again, assuming the clown is our main focus, the energy gained by the throw simply equals (1/2)(Clown mass)(Final clown velocity)².

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c) The energy gained, as well as the movement of the clown, is explained by Newton's Third Law of Motion. "For every action there is an equal and opposite reaction" might sound familiar. In this case, the clown acted on the barbell and the barbell reacted on her. Had she not been on ice, the friction of the ground would've kept her in place; but then you couldn't get a Physics problem out of it eh?

4 0
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1. A horizontal force of 50 N is applied to push a desk 40 m across a
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