The moles of hydrogen produced in the reaction has been 0.105 mol. Hence, option D is correct.
The balanced chemical equation for the decomposition of Ammonia has been:
<h3>Computation for moles of Hydrogen produced</h3>
From the balanced chemical equation, decomposition of 2 moles of ammonia produces, 3 moles of hydrogen and 1 mole, nitrogen.
The moles of hydrogen produced along with 0.0351 mol nitrogen has been:
Thus, the moles of hydrogen produced in the reaction has been 0.105 mol. Hence, option D is correct.
Learn more about balanced equation, here:
brainly.com/question/7181548
The answer is: " NaCl + H₂O " ; (or; write as: " H₂O + NaCl " ) .
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Specifically:
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HCl + NaOH —> NaCl + H₂O ; or; write as:
NaOH + HCl —> H₂O + NaCl .
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This type of "double-replacement" reaction is called "neutralization".
Since we are adding a strong acid to a strong base (reactants), we know that the product will be: 1) a salt ; and 2) water. Since we know one of the reactants will be "water" (H₂O) ; we can find the base (i.e. , the "remaining product") from selecting the "unused elements" to form the corresponding "salt".
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Answer:
B. There is a very large percentage of C-12.
Explanation:
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In this case, according to the given information, it turns out possible for us to realize that, since the average atomic mass is 12.01 amu, then the C-12, with an atomic mass of 12.000 am prevails over C-13 with an atomic mass of 13.003 amu as long as the average is nearer to the former.
In such a way, the answer will be B. There is a very large percentage of C-12.
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