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Nostrana [21]
3 years ago
11

Carbon and oxygen combine chemically to form carbon dioxide. This means that carbon dioxide is a ________.

Physics
2 answers:
AlekseyPX3 years ago
7 0
It is a chemical compound
AlexFokin [52]3 years ago
7 0
Carbon dioxide is a compound which is done by the elements carbon and oxygen chemically joined together
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What happens in the process of gravitational condensation?
Lerok [7]

Answer:

An object decreases in size due to the collision of materials. An object increases in size due to the addition of materials. Gas particles are formed from solar nebula materials.

3 0
3 years ago
In order to start an object moving, you must first overcome the force of _________ friction.
navik [9.2K]
It would be static friction which is what you have to overcome when an object is not in motion. When you move an object friction works against it like gravity and air resistance. I hope this helps!
7 0
3 years ago
Read 2 more answers
At the very end of Wagner's series of operas The Ring of Nibelung, Brunnhilde takes the golden ring form the finger of the dead
Blababa [14]

Answer:

a) 404 m² b) apparent height = 7.5 m

Explanation:

This question is about refraction and total internal refraction.

Here I will take refractive index of air and water

n_{air}=1\\ n_{water}=1.33=4/3

Now let's look at the diagram I have attached here

At some angle A, the light from the ring (yellow point) under water will be totally internally refracted (B = 90°), which means that rays of light (yellow arrow) that make large enough angle A will not be able to escape from the water. Since we assumed that the ring is a point, there will be a critical cone of angle A with the ring at its apex which traces a circle of radius R on the surface of water, which, beyond this radius, no light could escape.

According to snell's law

\frac{sin(B)}{sin(A)} = \frac{n_{water}}{n_{air}} = 4/3

At critical angle B = 90°

\frac{3)}{4}sin(B) = [tex]\frac{3}{4} sin(90^\circ ) = 0.75 = sin(A)

Therefore

A = 48.6^\circ

With this, we can find the radius of the circle (refer to my diagram)

h* tan (A) = R\\R =11.3 m

And with that we can find the area

A = \pi R^2=404\ m^2

Additional Problem

For apparent depth from above, we can think that, since we are accustomed to seeing light at the speed of c in air, our brain interpret light from <em>any</em> source to be traveling at c. This causes light that originated under water, which has the speed of

v_{water} = \frac{c}{n_{water}} = 0.75c

to appear as if it has traveled with the same duration as light with speed c

In order for this to happen our brain perceive shortened length  which is the apparent depth.

To put it in mathematical term

t_{travel}=\frac{h_{apparent}}{v_{water}} =\frac{h}{c}

So we get apparent depth

h_{apparent}=0.75h = 7.5\ m

4 0
3 years ago
Una pelota de béisbol es arrojada verticalmente hacia arriba desde la azotea de un edificio con una velocidad de 20m/s. Calcular
ExtremeBDS [4]

buenos dias senor, en ingles por favor/per favore ???

5 0
3 years ago
If 2050 J of heat are added to a 150 g object its temperature increases by 15°C.
Darina [25.2K]

When an object gets heated by a temperature ΔT energy needed, E = mcΔT

Here energy is given E = 2050 J

Mass of object = 150 g

Change in temperature ΔT  = 15 ^0C = 15 K

a) Heat capacity of an object equal to the ratio of the heat added to (or removed from) an object to the resulting temperature change.

  So heat capacity = E/ΔT = 2050/15 = 136.67 J/K

b) We have E = mcΔT

                    c = \frac{2050}{150*10^{-3}*15}  = 911.11 J/kgK

 So object's specific heat = 911.11 J/kgK

5 0
3 years ago
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